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I can't using the following method because my class doesn't extends the Activity class: Is there a unique Android device ID?

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Rotem E
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    pass the context object to the method. – Blackbelt Jun 19 '14 at 12:15
  • Make your class Member object static . Then You can use like `Class.member` will work. – Shabbir Dhangot Jun 19 '14 at 12:17
  • Take a look at these questions -> http://stackoverflow.com/questions/2785485/is-there-a-unique-android-device-id http://stackoverflow.com/questions/16078269/android-unique-serial-number/16929647#16929647 – faraway Jun 19 '14 at 12:48
  • Thanks for all answers, But because I didn't using the activity class, I cant access to the context object. I do instrumentation to another apk and this is the reason that I cant use the activity class. All your solutions deals using with the Activity class (directly or indirectly) – Rotem E Jun 19 '14 at 13:37
  • ...send the Context in a constructor parameter – EpicPandaForce Jun 19 '14 at 14:02

2 Answers2

1

Try like this

import android.content.Context;
import android.provider.Settings.Secure;

public class sample {


    public String getId(Context c)
    {

         String android_id = Secure.getString(c.getContentResolver(),
                                                                    Secure.ANDROID_ID); 

         return android_id;
    }
}

pass the context from your activity

sample s=new sample();

    String udid=s.getId(getApplicationContext());
    Toast.makeText(getApplicationContext(), udid, Toast.LENGTH_LONG).show();
George Thomas
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  • Thanks for the answer, But because I didn't using the activity class, I cant access to the context object. I do instrumentation to another apk and this is the reason that I cant use the activity class. – Rotem E Jun 19 '14 at 12:39
0

Try like this

public class Sample {


public static String getId(Context c)
{

     String android_id = Secure.getString(c.getContentResolver(),
                                                                Secure.ANDROID_ID); 

     return android_id;
    }
}

when you need the device id 

String id = Sample.getId(youractivity.this);// if ur in an activity

or try this

 String id =Sample.getId(getApplicationContext());
Nithinlal
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