write file even in case of any interruption

Question

How to make sure that file is written in case of any kind of interruption? Consider this code

with open('output.txt', 'a') as FH:
    for i in range(5):
        mystr = 'some text %d\n' %i
        FH.write(mystr)
        time.sleep(2)

If this code is running and you interrupt it using Ctrl+c it still writes the output file. But if you use Ctrl+z it do not write anything in the file!

What you want to do is catch the kill signal, and then ignore it. Though you'll then essentially have an un-killable app, so make sure you don't have an infinite loop or anything — wnnmaw, Jul 31 '14 at 11:27
Do you mean you want to do all 5 writes, even if you interrupt it after 2 writes? Or do you just want to flush the buffer to the file when the user presses Ctl-C. — Barmar, Jul 31 '14 at 11:28
Relevant: http://stackoverflow.com/questions/2148888/python-trap-all-signals — wnnmaw, Jul 31 '14 at 11:33
@Barmar I "just want to flush the buffer to the file when the user presses Ctl-C or ctl-z or any other kind of kill signal — d.putto, Jul 31 '14 at 11:34

score 3 · Answer 1 · answered Jul 31 '14 at 11:39

3

Flush the buffer immediately after writing it:

FH.write(mystr)
FH.flush()

answered Jul 31 '14 at 11:39

Barmar

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write file even in case of any interruption

1 Answers1