Run .jar from batch-file

Question

I have created an executable .jar file. How can I execute the .jar using a batch-file without mentioning a class path?

Dude, formatting, a question is not a code segment. – Jonno_FTW Apr 12 '10 at 12:40 — Jonno_FTW, Apr 12 '10 at 12:40

score 61 · Answer 1 · answered Dec 09 '11 at 13:38

61

On Windows you can use the following command.

start javaw -jar JarFile.jar

By doing so, the Command Prompt Window doesn't stay open.

answered Dec 09 '11 at 13:38

Jleuleu

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Windows cannot find 'javaw'. I fixed this by just having `start JarFile.jar` (with the .jar file in the same folder as the batch file). – NiteCyper Nov 21 '14 at 13:39
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OMG! How do you stop it now? – shyam May 21 '15 at 09:27
when I use start I am getting "windows cannot find '-jar'. Make sure you type the name correctly..." – Navakanth Feb 27 '17 at 11:07
Combining answers: `start javaw -jar %~dp0JarFile.jar %*` – roy Apr 15 '19 at 06:03
How do we stop it now? – Waqas Apr 06 '20 at 08:20

BrunoMedeiros · Answer 2 · 2014-01-16T17:38:12.600

There is a solution to this that does not require to specify the path of the jar file inside the .bat. This means the jar can be moved around in the filesystem with no changes, as long as the .bat file is always located in the same directory as the jar. The .bat code is:

java -jar %~dp0myjarfile.jar %*

Basically %0 would expand to the .bat full path, and %~dp0 expands to the .bat full path except the filename. So %~dp0myjarfile.jar is the full path of the myjarfile.jar colocated with the .bat file. %* will take all the arguments given to the .bat and pass it to the Java program. (see: http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/percent.mspx?mfr=true )

score 20 · Answer 3 · edited Jul 11 '17 at 12:02

20

You can create a batch file with .bat extension with the following contents

Use java for .jar that does not have UI and is a command line application

@ECHO OFF
start java -jar <your_jar_file_name>.jar

Use javaw for .jar that has a UI

@ECHO OFF
start javaw -jar <your_jar_file_name>.jar

Please make sure your JAVA_HOME is set in the environment variables.

edited Jul 11 '17 at 12:02

k32y

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answered Jul 09 '14 at 06:56

Nagarajan S R

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Precise and accurate info.Much obliged! – With A SpiRIT Feb 12 '16 at 08:49

score 16 · Answer 4 · answered Apr 12 '10 at 12:42

16

If you want a batch file to run a jar file, make a blank file called runjava.bat with the contents:

java -jar "C:\myjarfile.jar"

answered Apr 12 '10 at 12:42

Jonno_FTW

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score 10 · Answer 5 · edited Dec 14 '17 at 11:31

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cd "Your File Location without inverted commas"

example : cd C:\Users*****\Desktop\directory\target

java -jar myjar.jar

example bat file looks like this:

@echo OFF
cd C:\Users\****\Desktop\directory\target
java -jar myjar.jar

This will work fine.

edited Dec 14 '17 at 11:31

Kruti Patel

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answered Jan 30 '13 at 05:34

User123456

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Why without inverted commas (quotation mark)? If the path has a space in the name, you need the inverted commas. – Rob Jan 30 '13 at 05:56

score 7 · Answer 6 · answered Apr 12 '10 at 12:41

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To run a .jar file from the command line, just use:

java -jar YourJar.jar

To do this as a batch file, simply copy the command to a text file and save it as a .bat:

@echo off
java -jar YourJar.jar

The @echo off just ensures that the second command is not printed.

answered Apr 12 '10 at 12:41

mdm

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@Carlos: I assumed that as the OP asked for a batch file, that they were using Windows. – mdm Apr 12 '10 at 14:20
I am using windows 7.I have the jar file in the D:\my.jar I write the following code in my batch file @echo off java -jar my.jar and also i tried @echo off java -jar D:\my.jar what can i do? – Arivu2020 Apr 13 '10 at 10:54

RichieHindle · Answer 7 · 2010-04-12T12:46:32.553

4

If double-clicking the .jar file in Windows Explorer works, then you should be able to use this:

start myapp.jar

in your batch file.

The Windows start command does exactly the same thing behind the scenes as double-clicking a file.

edited Apr 12 '10 at 12:46

answered Apr 12 '10 at 12:40

RichieHindle

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It gives the error windows cannot find myapp.jar(my jar file). – Arivu2020 Apr 13 '10 at 05:52
@Arivu2020: Are you in the right directory? Perhaps your batch file need to do `cd c:\path\to\my\stuff` before trying to run the jar file? – RichieHindle Apr 13 '10 at 08:41

score 2 · Answer 8 · answered Jan 27 '17 at 07:04

you can use the following command in the .bat file newly created:

@echo off
call C:\SWDTOOLS\**PATH\TO\JAVA**\java_1.7_64\jre\bin\java -jar workspace.jar

Please give the path of the java if there are multiple versions of java installed in the system and make sure you specified the main method and manifest file is created while creating the jar file.

score 2 · Answer 9 · edited Jan 02 '12 at 10:46

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java -jar "C:\\myjarfile.jar"

You might need to add "\\" to the command. Try this!

edited Jan 02 '12 at 10:46

sra

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answered Sep 06 '11 at 22:59

Venkat

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score 1 · Answer 10 · answered May 11 '16 at 08:15

You need to make sure you specify the classpath in the MANIFEST.MF file. If you are using Maven to do the packaging, you can configure the following plugins:

1. maven-depedency-plugin:
2. maven-jar-plugin:

<plugin>
    <artifactId>maven-dependency-plugin</artifactId>
    <version>${version.plugin.maven-dependency-plugin}</version>
    <executions>
        <execution>
            <id>copy-dependencies</id>
            <phase>package</phase>
            <goals>
                <goal>copy-dependencies</goal>
            </goals>
            <configuration>
                <outputDirectory>${project.build.directory}/lib</outputDirectory>
                <overWriteReleases>false</overWriteReleases>
                <overWriteSnapshots>true</overWriteSnapshots>
                <includeScope>runtime</includeScope>
            </configuration>
        </execution>
    </executions>
</plugin>
<plugin>
    <artifactId>maven-jar-plugin</artifactId>
    <version>${version.plugin.maven-jar-plugin}</version>
    <configuration>
        <archive>
            <manifest>
                <addClasspath>true</addClasspath>
                <classpathPrefix>lib/</classpathPrefix>
                <addDefaultImplementationEntries>true</addDefaultImplementationEntries>
                <addDefaultSpecificationEntries>true</addDefaultSpecificationEntries>
            </manifest>
        </archive>
    </configuration>
</plugin>

The resulting manifest file will be packaged in the executable jar under META-INF and will look like this:

Manifest-Version: 1.0
Implementation-Title: myexecjar
Implementation-Version: 1.0.0-SNAPSHOT
Built-By: razvanone
Class-Path: lib/first.jar lib/second.jar
Build-Jdk: your-buildjdk-version
Created-By: Maven Integration for Eclipse
Main-Class: ro.razvanone.MyMainClass

The Windows script would look like this:

@echo on
echo "Starting up the myexecjar application..."
java -jar myexecjar-1.0.0-SNAPSHOT.jar

This should be complete config for building an executable jar using Maven :)

score 1 · Answer 11 · answered Jan 02 '12 at 10:51

My understanding of the question is that the OP is trying to avoid specifying a class-path in his command line. You can do this by putting the class-path in the Manifest file.

In the manifest:

Class-Path: Library.jar

This document gives more details:

http://docs.oracle.com/javase/tutorial/deployment/jar/downman.html

To create a jar using the a manifest file named MANIFEST, you can use the following command:

jar -cmf MANIFEST MyJar.jar <class files>

If you specify relative class-paths (ie, other jars in the same directory), then you can move the jar's around and the batch file mentioned in mdm's answer will still work.

score 0 · Answer 12 · answered Apr 12 '10 at 12:41

0

Just the same way as you would do in command console. Copy exactly those commands in the batch file.

answered Apr 12 '10 at 12:41

BalusC

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score 0 · Answer 13 · answered Jul 26 '18 at 17:04

Steps 1- Create/export a runnable jar file out of your project.

2- Create a .bat file with the below content

@Echo off

set classpath="c:\jars\lib\*****.jar;c:\jars\lib\*****.jar;c:\extJars\****.jar"

java -cp %classpath%;c:\apps\applName\yourJar.jar com.****.****.MainMethod args1 args2 ...

@pause

3- set classpath is required if any external jars you are using.

4- Put the .bat file and jar file in the same folder.

5- As per the java -cp command give your exact jar file location and the fully qualified name of the main method and followed by argument list as per requirement.

score -1 · Answer 14 · edited Jun 20 '20 at 09:12

-1

inside .bat file format

SET CLASSPATH=%Path%;

-------set java classpath and give jar location-------- set classpath=%CLASSPATH%;../lib/MoveFiles.jar;

---------mention your fully classified name of java class to run, which was given in jar------ Java com.mits.MoveFiles pause

edited Jun 20 '20 at 09:12

Community

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answered May 17 '19 at 09:21

ganesh vechalapu

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score -2 · Answer 15 · answered Aug 23 '13 at 07:33

-2

you shoult try this one :

java -cp youJarName.jar your.package.your.MainClass

answered Aug 23 '13 at 07:33

Burhan ARAS

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Run .jar from batch-file

15 Answers15

SET CLASSPATH=%Path%;

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