Java read file within .exe program

Question

I generated an .exe file from my jar using Launch4j. I was using ZipInputStream to read files inside my .jar before but now it is not working anymore (zip.getNextEntry() returns null).

The only solution I found was to drop the .exe and use a Runnable jar instead. Is it the only solution though ?

You should be using `Class.getResourceAsStream` to load resources. — teppic, Jan 16 '17 at 20:28
Sorry let me rephrase what I mean: how to browser the file inside the .exe to get their name ? — Lasbleis, Jan 16 '17 at 20:31
Use a library like [Reflections](https://github.com/ronmamo/reflections) to do the heavy lifting for you. — teppic, Jan 16 '17 at 21:31

score 1 · Accepted Answer · edited May 23 '17 at 11:45

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Why would you use a .exe? Do you have to? Otherwise just provide a .bat file which executes the java command to start the jar.

Put this into myapp.bat

start javaw -jar myapp.jar

see Run .jar from batch-file

edited May 23 '17 at 11:45

Community

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answered Jan 16 '17 at 20:26

Frieder

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Its rather for aestetic purpose: having a custom icon for my application and a custom one in the task bar since my program is for a video game – Lasbleis Jan 16 '17 at 20:28
You can change the icon in the task bar afaik and provide an icon for your .bat file too. See http://stackoverflow.com/questions/10575541/modifying-taskbar-icon-of-my-jar-program and in general you don't want to ship your java app as .exe except you will provide your own jre. Otherwise you still need java installed. – Frieder Jan 16 '17 at 20:34
If you are going to do that, I'd look at using Java Web Start rather than a bat file. http://stackoverflow.com/questions/1453369/i-have-never-seen-a-software-be-released-as-jar-so-how-can-i-make-a-software-be/1453477#1453477 – Michael Lloyd Lee mlk Jan 16 '17 at 20:55

Java read file within .exe program

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