display a series of interfaces using Tkinter in python

Question

In the following program, instead of displaying the interfaces one by one, it directly displays the 3rd interface when the Run button is pressed.

import Tkinter

root = Tkinter.Tk(  )
root.title("My First Game")

for r in range(3):
    for c in range(3):
        Tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
        Tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=2)
        Tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=1,column=3)
        Tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
        Tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
        Tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=2,column=3)
        Tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
        Tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
        Tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)

def mainprg():
    for r in range(3):
        for c in range(3):
            Tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
            Tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=2)
            Tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=1,column=3)
            Tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
            Tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
            Tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=2,column=3)
            Tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
            Tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
            Tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)


B = Tkinter.Button(root, text = "Run", command = mainprg)
B.grid(row = 4, column = 1)



def mainprg1():
    for r in range(3):
        for c in range(3):
            Tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
            Tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=1,column=2)
            Tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=3)
            Tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
            Tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
            Tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=2,column=3)
            Tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
            Tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
            Tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)


B = Tkinter.Button(root, text = "Run", command = mainprg1)
B.grid(row = 4, column = 1)
root.mainloop()

What should i do to display a series of interfaces by clicking the Run button?

your indentation is wrong in the first loop. Other than that I'm not entirely sure why you are looping. at no point are you using the r or c values in the loop, you are simply doing the same thing 9 times - in that you are gridding set labels to set places. — NDevox, Oct 10 '14 at 14:02
...you put the button that calls `mainprg1` **on top of** the button that calls `mainprg`; what did you expect to happen? Again, you should have a look at e.g. http://stackoverflow.com/a/26213779/3001761 rather than just randomly packing in more widgets. And as @Scironic points out, the `for` loops are (still) pointless. — jonrsharpe, Oct 10 '14 at 14:03
I have corrected the indentation and removed the loops. What should i do to display the interfaces one by one? When i press the Run button, it directly jumps to the last interface skipping the interfaces in between. — bio-terror, Oct 10 '14 at 14:08
Yes, because the `Run` button you see is the one that calls `mainprg1`, **not** the one that calls `mainprg`, because you've *put the newer button **on top of** the older one*. — jonrsharpe, Oct 10 '14 at 14:09

NDevox · Accepted Answer · 2014-10-10T14:30:37.763

Having run you're program I now understand what you are asking.

At the moment you define the command for the button to be mainprg() and then cover it with a button that will run mainprg1().

If you remove the second definition for B:

B = Tkinter.Button(root, text = "Run", command = mainprg1)
B.grid(row = 4, column = 1)

and place this within your mainprg() function:

B.configure(command = mainprg1)

It should work.

Edit: fixed the details thanks to jonrsharpe

Edit2: Here is my working code (in Python 3.4 - note that Tkinter is now tkinter - I also added a command redefinition in mainprg1 back to mainprg, just for kicks.

import tkinter

root = tkinter.Tk(  )
root.title("My First Game")

tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=2)
tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=1,column=3)
tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=2,column=3)
tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)

def mainprg():

    tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
    tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=2)
    tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=1,column=3)
    tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
    tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
    tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=2,column=3)
    tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
    tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
    tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)

    B.configure(command = mainprg1)

B = tkinter.Button(root, text = "Run", command = mainprg)
B.grid(row = 4, column = 1)



def mainprg1():
    tkinter.Label(root, text= '3', borderwidth=20 ).grid(row=1,column=1)
    tkinter.Label(root, text= ' ', borderwidth=20 ).grid(row=1,column=2)
    tkinter.Label(root, text= '6', borderwidth=20 ).grid(row=1,column=3)
    tkinter.Label(root, text= '2', borderwidth=20 ).grid(row=2,column=1)
    tkinter.Label(root, text= '7', borderwidth=20 ).grid(row=2,column=2)
    tkinter.Label(root, text= '4', borderwidth=20 ).grid(row=2,column=3)
    tkinter.Label(root, text= '5', borderwidth=20 ).grid(row=3,column=1)
    tkinter.Label(root, text= '1', borderwidth=20 ).grid(row=3,column=2)
    tkinter.Label(root, text= '8', borderwidth=20 ).grid(row=3,column=3)

    B.configure(command = mainprg)

root.mainloop()

There is no "redefining" of the command - the OP puts a brand new button on top of the old one and assigns it to the same name — jonrsharpe, Oct 10 '14 at 14:11
Placing it within the mainprg() function, it gives an error saying that "name 'mainprg1' is not defined. — bio-terror, Oct 10 '14 at 14:21
I'm working in Python 3.4 so might be some differences in how globals work but I've not got any problems. I'll paste in what I have above. — NDevox, Oct 10 '14 at 14:28
Finally got it working!!! Thank you @Scironic. One last thing, how can i display these interfaces by clicking the Run button once? — bio-terror, Oct 10 '14 at 14:41
All interfaces simultaneously? as in multiple windows, or progressing through the interfaces through time? or something else? — NDevox, Oct 10 '14 at 14:48
progressing through time with a single click at the beginning! — bio-terror, Oct 10 '14 at 15:05

display a series of interfaces using Tkinter in python

1 Answers1