In the below random array:
a = [[1,2,3,4],
[6,7,8,9]]
Could you please tell me how to remove element at a specific position. For example, how would I remove a[1][3]?
I understand list.pop is used for only list type DS here.
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4 Answers
7
Simple, just pop on the list item.
>>> a = [[1,2,3,4], [6,7,8,9]]
>>> a[1].pop(3)
>>> a
[[1, 2, 3, 4], [6, 7, 8]]
nathancahill
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2
You should use del to remove an item at a specific index:
>>> a = [[1,2,3,4], [6,7,8,9]]
>>> del a[1][3]
>>> a
[[1, 2, 3, 4], [6, 7, 8]]
>>>
list.pop should only be used when you need to save the value you just removed.
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If we remove one element from a column , for example , from bottom of a column, then how to adjust the element in that column ? – Bravo Oct 27 '17 at 11:24
0
You can use any of the three method:
- Remove
- Pop
- del
a = [[1,2,3,4], [6,7,8,9]]
1- Remove a[1].remove(a[1][3])
2- Pop a[1].pop(3)
3-Del del a[1][3]
shubham khantwal
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To make your answer clearer, have a look at using code blocks - see the 'help' option while writing/editing your answer. – dspencer Mar 15 '20 at 15:00
