Deleting a string from a one list with strings/numbers

Question

I have a list that looks like this -

item1,5,1,648,16,10,0,3,5,1,1,0,1,1,1,0,0,0,0,0,1,0,0,1,0,0
item2,3,1,29,3,6,0,0,3,1,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0
item3,4,1,2388,20,8,2,0,3,1,1,0,0,1,0,0,0,0,0,0,1,1,0,0,0,0
item4,6,3,0,0,1,0,0,5,1,0,1,1,1,0,1,0,0,0,0,0,0,1,1,1,0

What would be the best way of deleting the "item" part of the list?

I've tried

del list[j][0]

But then I get "TypeError: 'str' object doesn't support item deletion"

I've tried

list[j].remove(list[j][0])

But then I get AttributeError: 'str' object has no attribute 'remove'

Pop doesn't seem to work either - AttributeError: 'str' object has no attribute 'pop'

Any ideas?

EDIT: So I've read in a list -

data = open("flags.features", 'r').readlines()

Then just split each line -

for i in data:
    input_list.append(i.split('\n')[0])

With an output of -

['item1,5,1,648,16,10,0,3,5,1,1,0,1,1,1,0,0,0,0,0,1,0,0,1,0,0',         'item2,3,1,29,3,6,0,0,3,1,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0', 'item3,4,1,2388,20,8,2,0,3,1,1,0,0,1,0,0,0,0,0,0,1,1,0,0,0,0', 'item4,6,3,0,0,1,0,0,5,1,0,1,1,1,0,1,0,0,0,0,0,0,1,1,1,0', 'item5,3,1,0,0,6,3,0,3,1,0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0', '

Does this answer your question? [How to delete empty strings from a 2d list](https://stackoverflow.com/questions/57983240/how-to-delete-empty-strings-from-a-2d-list) — Blue Robin, Mar 19 '22 at 02:28
Is it 1D or 2D list? It seems like you are having a 1D list. — KONG VUNGSOVANREACH, Mar 19 '22 at 02:34
it is a 1D list. So if you access by list[j], you will get a string. You cannot use any list methods on the string. — KONG VUNGSOVANREACH, Mar 19 '22 at 02:39

score 2 · Answer 1 · answered Mar 19 '22 at 02:43

2

You may try this:

my_list = [x.split(",") for x in my_list]
my_list[j].pop(0)

answered Mar 19 '22 at 02:43

KONG VUNGSOVANREACH

176
3

score 2 · Accepted Answer · answered Mar 19 '22 at 02:44

How about this?

data = open("flags.features", 'r').readlines()
input_list = []

for i in data:
    input_list.append(",".join(i.split('\n')[0].split(",")[1:]))

This outputs

['5,1,648,16,10,0,3,5,1,1,0,1,1,1,0,0,0,0,0,1,0,0,1,0,0',
 '3,1,29,3,6,0,0,3,1,0,0,1,0,1,0,0,0,0,0,1,0,0,0,1,0',
 '4,1,2388,20,8,2,0,3,1,1,0,0,1,0,0,0,0,0,0,1,1,0,0,0,0',
 '6,3,0,0,1,0,0,5,1,0,1,1,1,0,1,0,0,0,0,0,0,1,1,1,0']

score 1 · Answer 3 · answered Mar 19 '22 at 02:31

1

You could do:

list[j].pop(1) #the 1 can be replaced with any number

This will index the list then pop the item in that list off.

This question is also very similar to: Using pop for removing element from 2D array

answered Mar 19 '22 at 02:31

Blue Robin

847
2
11
31

Yes, I've tried that but I get AttributeError: 'str' object has no attribute 'pop' – tobytobias Mar 19 '22 at 02:32
@tobytobias could you show the full list and code? That could help. – Blue Robin Mar 19 '22 at 02:33
I added a bit more detail in the post @Blue Robin – tobytobias Mar 19 '22 at 02:38
Does appending it without the newline work? @tobytobias – Blue Robin Mar 19 '22 at 02:42
So you're saying instead of split at \n, I change how I input it, so it doesn't have the Item part? – tobytobias Mar 19 '22 at 02:44
1

@tobytobias I'm not sure. But other answers seem very useful. – Blue Robin Mar 19 '22 at 02:50
Yep, I've figured it out, thank you very much for your help! – tobytobias Mar 19 '22 at 02:52
You are welcome @tobytobias I tried my best – Blue Robin Mar 19 '22 at 02:53

Deleting a string from a one list with strings/numbers

3 Answers3