When I try to encrypt the ciphertext again with the same key, it produces the original plaintext.
Algoritm used is AES with COUNTER MODE. Key and IV remains the same.
Is this the way the algorithm is supposed to behave? And if, what is the use of Cipher.ENCRYTMODE which is to be given as the first parameter of Cipher.init()?
Here is the sample program with which I tested,
import javax.crypto.*;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
public class EncryptionTest {
public static void main(String[] args) throws Exception {
SecretKeySpec key = null;
IvParameterSpec ivSpec = null;
byte[] keyBytes = "usethiskeyusethiusethiskeyusethi".getBytes();
byte[] ivBytes = "usethisIusethisI".getBytes();
key = new SecretKeySpec(keyBytes, "AES"); //No I18N
ivSpec = new IvParameterSpec(ivBytes);
Cipher AesCipher = Cipher.getInstance("AES/CTR/NoPadding");
byte[] byteText = "Your Plain Text Here".getBytes();
AesCipher.init(Cipher.ENCRYPT_MODE, key, ivSpec);
byte[] byteCipherText = AesCipher.doFinal(byteText);
System.out.println("Encrypted : " + new String(byteCipherText));
AesCipher.init(Cipher.ENCRYPT_MODE, key, ivSpec);
byte[] bytePlainText = AesCipher.doFinal(byteCipherText);
System.out.println("Double Encrypted : " + new String(bytePlainText));
}
}