lamba functions with different parameters inside a loop

Asked Dec 09 '15 at 12:05

Active Aug 18 '22 at 02:27

Viewed 95 times

I have created a small GUI in which I want to create buttons in a loop which are supposed to open a text file. The function to open the textfile stands in another python module which I have included:

def openTextEditor(textfile):
"""opens the textfile with path 'textfile' """
    [...]

In my actual loop I try to assign different paths to the buttons:

for path in foobar:
    print path
    tk.Button(text="EDIT",
              relief="tk.RAISED",
              bg='black',
              fg='white',
              command= lambda: openTextEditor(path) ).grid(row=r, column=c)

From this post I know that I have to use a lamda expression in order to pass a parameter as button command.

However, my console prints different paths to text files:

path1
path2
path3

while all of my 3 buttons open text file with path3. I assume that only the last assignment of the lambda function has effect, but why?

edited May 23 '17 at 12:15

Community

asked Dec 09 '15 at 12:05

h0ch5tr4355

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BTW: I had problems to find an accurate title and so I had problems to find similar questions. I think this problem raised in another form already. – h0ch5tr4355 Dec 09 '15 at 12:09
2

Duplicate, but can't find it right now. Try `lambda path=path: openTextEditor(path)` – tobias_k Dec 09 '15 at 12:15
@tobias_k thanks that worked, should I close it? – h0ch5tr4355 Dec 09 '15 at 12:17

lamba functions with different parameters inside a loop

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