i have 4 select
boxes in my webpage, 1st type, 2nd province, 3rd genre, 4 th user, i need to filter the 3rd and 4th select
drop down boxes based on the 1st and 2nd, ie if i select
buy beats in 1st and a province in 2nd, the 4th box should display the beat makers in that selected province and the 3rd box is based on the 1st its working properly. My problem the user box not displaying the user of particular province.
I have given my code below please help
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="send_request.php" name="myForm1" method="post" onsubmit="return(validate1());">
<div class="sec1 lef">
<select class="regtext sec1test" name="select" id="select1" style="width:99%">
<option value="0">Select What?</option>
<option value="1">Features</option>
<option value="2">Video-shoot</option>
<option value="3">Buy Lyrics</option>
<option value="4">Buy Beats</option>
</select>
</div>
<div class="sec1 lef">
<select class="regtext sec1test" name="province" style="width:99%">
<option value="0">Select Province</option>
<?php
$select_province=mysql_query("SELECT * FROM `wilinkit_province` WHERE 1");
while($fetch_province=mysql_fetch_array($select_province))
{
echo "<option value='".$fetch_province['province_id']."'>".$fetch_province['province_name']."</option>";
}
?>
</select>
</div>
<div class="sec1 lef">
<select name="type" class="regtext sec1test" id="select2" style="width:99%">
<option id="0" value="0">Select genre</option>
<?php
$select_genre=mysql_query("SELECT * FROM `wilinkit_genre` WHERE 1");
while($fetch_genre=mysql_fetch_array($select_genre))
{
echo "<option value='".$fetch_genre['genre_id']."' data-id='1'>".$fetch_genre['genre_name']."</option>";
}
?>
<option value="2" data-id="2">models</option>
<option value="3" data-id="3">Composer</option>
<option value="4" data-id="4">Beatmaker</option>
</select>
</div>
<div class="sec1 lef">
<select name="name" class="regtext sec1test" id="select3" style="width:99%">
<option id="0" value="0">Select User</option>
<?php
$select_artist111=mysql_query("SELECT * FROM `wilinkit_users` WHERE 1");
while($fetch_artist111=mysql_fetch_array($select_artist111))
{
$user_type=$fetch_artist111['user_type'];
echo "<option value=".$fetch_artist111['username']." data-id='".$user_type."'>".$fetch_artist111['username']."</option>";
}
?>
</select>
</div>
<div class="sec2 lef" >
<input type="submit" class="requestbutton" value="Request" />
</div>
</form>
<script type="text/javascript">
$(document).ready(function () {
var $select1=$("#select1");
var $select2=$("#select2");
var $select3=$("#select3");
$select1.data('options1', $select2.html())
$select1.data('options2', $select3.html())
$select1.change(function(){
var val=$select1.val();
var options1 = $($select1.data('options1')).filter('[data-id="'+val+'"]');
var options2 = $($select1.data('options2')).filter('[data-id="'+val+'"]');
$select2.html(options1);
$select3.html(options2);
});
});
</script>