How to programmatically open the WIFI settings in Objective-C on iOS 10

Question

The following code works fine on iOS 9, see this post. But it doesn't work on iOS 10. How to open WIFI settings programmatically on iOS 10

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=WIFI"]];

score 12 · Answer 1 · edited May 23 '17 at 12:32

12

The same exact code should work, but for iOS 10 you need to do some additional work by adding "prefs" to the URL Types:

After selecting your target:

Navigate to "Info" tab.
After scrolling to bottom, you should see "URL Types" section.
Add a new one (by clicking on the plus button) and fill the "URL Schemes" with "prefs".

It should be similar to this:

Now, your code should works fine.

UPDATE:

If it -somehow- did not work as expected, you might want to follow this workaround.

Hope that helped.

edited May 23 '17 at 12:32

Community

1
1

answered Oct 19 '16 at 09:17

Ahmad F

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1

openUrl is depreciated – gregm Jan 25 '17 at 16:04
2

You'll get rejected. They detect use of "prefs" urls now – matt Sep 04 '18 at 16:58

score 8 · Answer 2 · answered Feb 28 '17 at 16:07

8

In iOS 10, a new url is required. Try using this code which tests both urls :

NSArray* urlStrings = @[@"prefs:root=WIFI", @"App-Prefs:root=WIFI"];
for(NSString* urlString in urlStrings){
    NSURL* url = [NSURL URLWithString:urlString];
    if([[UIApplication sharedApplication] canOpenURL:url]){
        [[UIApplication sharedApplication] openURL:url];
        break;
    }
}

answered Feb 28 '17 at 16:07

Drico

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Unfortunatly no official documentation, but some pages already reference a lot of them, for example https://gist.github.com/phynet/471089a51b8f940f0fb4 – Drico Mar 16 '17 at 11:30
Unlike others this one worked for me also for iOS 10 – Marek Manduch Jul 13 '17 at 14:51
2

My app just got rejected for this. Do not use – matt Sep 15 '18 at 05:51

score 3 · Answer 3 · answered Dec 17 '16 at 12:00

Try this one :

    if([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]]) {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:UIApplicationOpenSettingsURLString]options:[NSDictionary dictionary] completionHandler:^(BOOL success) {
        }];
    }

Thanks :)

score 3 · Accepted Answer · answered Mar 21 '17 at 06:03

3

This works fine on iOS 10,

Go to Targets --> (Application) --> Info --> URL Types --> +

In the URL Schemes write

prefs

See the image,

Then add the following code,

-(void)openWifiSettings{
    if ([[UIApplication sharedApplication] canOpenURL:[NSURL URLWithString:@"prefs:root=WIFI"]]) {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"prefs:root=WIFI"]];
    } else {
        [[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"App-Prefs:root=WIFI"]];
    }
}

answered Mar 21 '17 at 06:03

Shuvo Joseph

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In iOS 11 `App-Prefs` takes me to the app specific preferences, not the wifi screen. – keegan3d Nov 06 '17 at 00:52
1

same question here: In iOS11 App-Prefs takes me to the app specific preferences, not the wifi screen. how to solve it in iOS11+ ? – imti May 19 '19 at 09:27

Alessandro Francucci · Answer 5 · 2018-10-22T11:22:39.033

2

Swift 4.2, iOS 12

It's not longer possible to do that kind of deeplinking with the newer version of iOS. My app was recently rejected for using: "non-public URL scheme", such as: prefs:root=. So I'd say to not waste your time with something that we can't currently do, and simply open the settings.

This is the function that I'm currently using in my app for it:

extension UIApplication {

    ...

    @discardableResult
    static func openAppSetting() -> Bool {
        guard
            let settingsURL = URL(string: UIApplicationOpenSettingsURLString),
            UIApplication.shared.canOpenURL(settingsURL)
            else {
                return false
        }

        UIApplication.shared.open(settingsURL)
        return true
    }
}

Usage: UIApplication.openAppSetting()

edited Oct 22 '18 at 11:22

answered Oct 22 '18 at 10:35

Alessandro Francucci

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so this will simply take to settings page and not exactly on wifi list page, correct ? – shaqir saiyed Aug 08 '19 at 12:53
1

Exactly, we can't open the settings page unfortunately. (or at least, not in a production app at the moment) – Alessandro Francucci Aug 10 '19 at 14:05

score -1 · Answer 6 · edited Mar 01 '17 at 11:16

-1

For Swift:

let url = URL(string: "App-Prefs:root=WIFI")

    if UIApplication.shared.canOpenURL(url!){
        UIApplication.shared.openURL(url!)

    }

edited Mar 01 '17 at 11:16

Alexander Farber

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answered Mar 01 '17 at 11:00

krishna

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This will get your app rejected – matt Sep 15 '18 at 05:52

score -2 · Answer 7 · answered Mar 22 '17 at 10:48

 let url=URL(string: "App-Prefs:root=WIFI")
// you can change root as your requirements 
        if UIApplication.shared.canOpenURL(url!)
        {
            UIApplication.shared.open(url!, options: [:], completionHandler: {success in

            })

        }
        else{
            UIApplication.shared.open(url!, options: [:], completionHandler: {success in

            })
        }

How to programmatically open the WIFI settings in Objective-C on iOS 10

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