125

i have this code:

app.controller('MainCtrl', function ($scope, $http){
  $http.get('api/url-api')
    .success(function (data, status, headers, config){
     }
}

In my local enviroment, works ok, but in a server, return this error:

TypeError: $http.get(...).success is not a function

Any ideas? Thanks

Mihai Alexandru-Ionut
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Alejo Ribes
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3 Answers3

242

The .success syntax was correct up to Angular v1.4.3.

For versions up to Angular v.1.6, you have to use then method. The then() method takes two arguments: a success and an error callback which will be called with a response object.

Using the then() method, attach a callback function to the returned promise.

Something like this:

app.controller('MainCtrl', function ($scope, $http){
   $http({
      method: 'GET',
      url: 'api/url-api'
   }).then(function (response){

   },function (error){

   });
}

See reference here.

Shortcut methods are also available.

$http.get('api/url-api').then(successCallback, errorCallback);

function successCallback(response){
    //success code
}
function errorCallback(error){
    //error code
}

The data you get from the response is expected to be in JSON format. JSON is a great way of transporting data, and it is easy to use within AngularJS

The major difference between the 2 is that .then() call returns a promise (resolved with a value returned from a callback) while .success() is more traditional way of registering callbacks and doesn't return a promise.

Mihai Alexandru-Ionut
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9

This might be redundant but the above most voted answer says .then(function (success) and that didn't work for me as of Angular version 1.5.8. Instead use response then inside the block response.data got me my json data I was looking for.

$http({
    method: 'get', 
    url: 'data/data.json'
}).then(function (response) {
    console.log(response, 'res');
    data = response.data;
},function (error){
    console.log(error, 'can not get data.');
});
Ian Poston Framer
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  • i mean... did you try `success.data`? the parameter name isn't that important in this case. – Kevin B May 04 '17 at 21:27
  • My code works. When I followed the above answer I got stuck. It is also an answer with a way to actually get the data and log it to your console. This can show developers how to test their data in their browser. I was led here by the same exact error in the question headline. – Ian Poston Framer May 04 '17 at 21:46
  • old code `$http.get('data/data.json').success(function(data) { data = data;}` with my answer a developer now knows its `data.data` can't just get data by itself. hence my answer is important to this error message. – Ian Poston Framer May 04 '17 at 22:05
  • The variable name will not make any difference, it could be `success.data` or `response.data` or anything else. You could even use `donaldTrump.data` that will work too. Although you should use sensible variable names, not sure this one will make much sense. – Gaurav Arya Dec 28 '17 at 12:35
  • This is because the **success** object has an array named `data` that holds the data coming as response from your server. you need to access that data array, using `.data` – Gaurav Arya Dec 28 '17 at 12:42
4

If you are trying to use AngularJs 1.6.6 as of 21/10/2017 the following parameter works as .success and has been depleted. The .then() method takes two arguments: a response and an error callback which will be called with a response object.

 $scope.login = function () {
        $scope.btntext = "Please wait...!";
        $http({
            method: "POST",
            url: '/Home/userlogin', // link UserLogin with HomeController 
            data: $scope.user
         }).then(function (response) {
            console.log("Result value is : " + parseInt(response));
            data = response.data;
            $scope.btntext = 'Login';
            if (data == 1) {
                window.location.href = '/Home/dashboard';
             }
            else {
            alert(data);
        }
        }, function (error) {

        alert("Failed Login");
        });

The above snipit works for a login page.

Waheed Rafiq
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