I don't understand what %s
and %d
do and how they work.

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12 Answers
They are used for formatting strings. %s
acts a placeholder for a string while %d
acts as a placeholder for a number. Their associated values are passed in via a tuple using the %
operator.
name = 'marcog'
number = 42
print '%s %d' % (name, number)
will print marcog 42
. Note that name is a string (%s) and number is an integer (%d for decimal).
See https://docs.python.org/3/library/stdtypes.html#printf-style-string-formatting for details.
In Python 3 the example would be:
print('%s %d' % (name, number))
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2In Google Chrome: Settings >> Search >> Manage search engines... notice how `%s` is used with search engine configurations. Chrome uses `%s` to replace keywords entered in the address bar. Python uses `%s` in a similar way. In `print('description: %s' % descrip)` the `%s` operator will be replaced by the text string stored in the `descrip` variable. The round braces prevent an error message in Python 3. – noobninja Aug 27 '16 at 20:51
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what do you call these %s, %d, etc? – Chaine May 19 '17 at 18:21
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1@Chaine they are called Placeholders, they are replaceable variables – Leo Jun 09 '17 at 19:44
from python 3 doc
%d
is for decimal integer
%s
is for generic string or object and in case of object, it will be converted to string
Consider the following code
name ='giacomo'
number = 4.3
print('%s %s %d %f %g' % (name, number, number, number, number))
the out put will be
giacomo 4.3 4 4.300000 4.3
as you can see %d
will truncate to integer, %s
will maintain formatting, %f
will print as float and %g
is used for generic number
obviously
print('%d' % (name))
will generate an exception; you cannot convert string to number

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8This deseeves more upvote. It explains what would happen if `%s` is used for a number instead. – Vikas Prasad Sep 01 '18 at 13:41
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2What is the difference between %d and %i, if both will convert to integer? How does %d compare to %i and %f ? – srini Jul 22 '19 at 12:05
%s
is used as a placeholder for string values you want to inject into a formatted string.
%d
is used as a placeholder for numeric or decimal values.
For example (for python 3)
print ('%s is %d years old' % ('Joe', 42))
Would output
Joe is 42 years old
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7Doesn't really explain the problem? I'm not explaining the problem, I'm providing a concise answer _to_ the question. The question specifically asked what %s and %d were for. – Soviut Feb 16 '12 at 02:37
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3do you know the difference between %i and %d? does python support %i? – cryanbhu Oct 31 '18 at 01:43
These are all informative answers, but none are quite getting at the core of what the difference is between %s
and %d
.
%s
tells the formatter to call the str()
function on the argument and since we are coercing to a string by definition, %s
is essentially just performing str(arg)
.
%d
on the other hand, is calling int()
on the argument before calling str()
, like str(int(arg))
, This will cause int
coercion as well as str
coercion.
For example, I can convert a hex value to decimal,
>>> '%d' % 0x15
'21'
or truncate a float.
>>> '%d' % 34.5
'34'
But the operation will raise an exception if the argument isn't a number.
>>> '%d' % 'thirteen'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: %d format: a number is required, not str
So if the intent is just to call str(arg)
, then %s
is sufficient, but if you need extra formatting (like formatting float decimal places) or other coercion, then the other format symbols are needed.
With the f-string
notation, when you leave the formatter out, the default is str
.
>>> a = 1
>>> f'{a}'
'1'
>>> f'{a:d}'
'1'
>>> a = '1'
>>> f'{a:d}'
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: Unknown format code 'd' for object of type 'str'
The same is true with string.format
; the default is str
.
>>> a = 1
>>> '{}'.format(a)
'1'
>>> '{!s}'.format(a)
'1'
>>> '{:d}'.format(a)
'1'

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4This should be the accepted answer. It's the only one that actually explains the difference. – Antimony Sep 23 '20 at 19:09
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2Given that I answered 9 years late, it's understandable. But, I was not satisfied with the answers so I added one. – Wyrmwood Sep 29 '20 at 20:51
These are placeholders:
For example: 'Hi %s I have %d donuts' %('Alice', 42)
This line of code will substitute %s with Alice (str) and %d with 42.
Output: 'Hi Alice I have 42 donuts'
This could be achieved with a "+" most of the time. To gain a deeper understanding to your question, you may want to check {} / .format() as well. Here is one example: Python string formatting: % vs. .format
also see here a google python tutorial video @ 40', it has some explanations https://www.youtube.com/watch?v=tKTZoB2Vjuk
The %d
and %s
string formatting "commands" are used to format strings. The %d
is for numbers, and %s
is for strings.
For an example:
print("%s" % "hi")
and
print("%d" % 34.6)
To pass multiple arguments:
print("%s %s %s%d" % ("hi", "there", "user", 123456))
will return hi there user123456

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1Note that `%d` is not any number. it's a decimal number (aka, integers). In the example above, `%d' %34.6` will output simply `34`. Same applies to `logger.info("value %d", 34.6)` – Snake Verde Feb 01 '22 at 00:21
%d
and %s
are placeholders, they work as a replaceable variable. For example, if you create 2 variables
variable_one = "Stackoverflow"
variable_two = 45
you can assign those variables to a sentence in a string using a tuple of the variables.
variable_3 = "I was searching for an answer in %s and found more than %d answers to my question"
Note that %s
works for String and %d
work for numerical or decimal variables.
if you print variable_3
it would look like this
print(variable_3 % (variable_one, variable_two))
I was searching for an answer in StackOverflow and found more than 45 answers to my question.

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As per latest standards, this is how it should be done.
print("My name is {!s} and my number is{:d}".format("Agnel Vishal",100))
Do check python3.6 docs and sample program

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Here is the basic example to demonstrate the Python string formatting and a new way to do it.
my_word = 'epic'
my_number = 1
print('The %s number is %d.' % (my_word, my_number)) # traditional substitution with % operator
//The epic number is 1.
print(f'The {my_word} number is {my_number}.') # newer format string style
//The epic number is 1.
Both prints the same.

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speaking of which ...
python3.6 comes with f-strings
which makes things much easier in formatting!
now if your python version is greater than 3.6 you can format your strings with these available methods:
name = "python"
print ("i code with %s" %name) # with help of older method
print ("i code with {0}".format(name)) # with help of format
print (f"i code with {name}") # with help of f-strings

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%s is used to hold space for string %d is used to hold space for number
name = "Moses";
age = 23
print("My name is %s am CEO at MoTech Computers " %name)
print("Current am %d years old" %age)
print("So Am %s and am %d years old" %(name,age))
this video goes deep about that tip https://www.youtube.com/watch?v=4zN5YsuiqMA

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Welcome to Stack Overflow! How is your answer different the other 12? – Vasil Velichkov Feb 17 '20 at 23:13
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almost those format works the same but all i wanted is to give more examples so as to increase an understanding – Noel Moses Mwadende Feb 20 '20 at 17:25
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That's great! You can improve your answer by adding the program output as a text and not as an image. – Vasil Velichkov Feb 20 '20 at 19:13
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thanks for your concern, i'll make some changes, you're welcome – Noel Moses Mwadende Feb 25 '20 at 19:40
In case you would like to avoid %s or %d then..
name = 'marcog'
number = 42
print ('my name is',name,'and my age is:', number)
Output:
my name is marcog and my name is 42

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2What does this answer have to do with the question? The questioner was asking about use of `%s` and `%d`. – Mark Dickinson Feb 03 '16 at 15:09
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BTW, the code you show is invalid in Python 3.5.1: `print` is a function in Python 3, not a statement. – Mark Dickinson Feb 03 '16 at 15:10
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I have edited the post ...please see it. Actually, I posted it as an alternative..if some one might avoid using %d or %s. And thanks for the error detection, ..I have edited the code. – Sujatha Feb 03 '16 at 17:37
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3Thanks for the edits. Unfortunately, this still isn't an answer to the question. – Mark Dickinson Feb 03 '16 at 18:03