Call of member function of objects in arrays

Asked Mar 19 '17 at 21:49

Active Mar 19 '17 at 21:49

Viewed 29 times

Given the following classes:

class animal {
public:
    virtual void noise() { };
};

class cat: public animal{
public:
    void noise() {
        cout << "mew" << endl;
    }
};

Why does this work (prints the correct noise):

animal *animals[2];
animals[0] = new dog;
animals[0]->noise();

But this doesn't:

animal animals[2];
dog dog1;
animals[0] = dog1;
animals[0].noise();

Is there a way to make it work without using pointers? The software wants me to add more text but I think I have already made my question very clear so this is just random text...

asked Mar 19 '17 at 21:49

Matt

Your real mistake is that the non-leaf base class is not abstract, as it better had be. – Kerrek SB Mar 19 '17 at 21:51
1

It has not become clear, hence me asking the question. – Matt Mar 19 '17 at 21:52
Which of those two results surprises you? And *why* do you want to make it work without pointers? – Beta Mar 19 '17 at 21:53
The second one not working surprises me. Because using new is to be avoided I was told. + out out sheer curiosity. – Matt Mar 19 '17 at 21:55

Call of member function of objects in arrays

0 Answers0