Encryption AES 128 with 2 different Result

Question

I'am trying to encrypt a String using AES-128 algorithm with given Key.

Implemented by Java, I used the solution here.

public static void main(String[] args) {
    String key = "Bar12345Bar12345"; // 128 bit key
    String initVector = "RandomInitVector"; // 16 bytes IV

    System.out.println(encrypt(key, initVector, "System")));
}

Result:

encrypted string: iHvz04u8X7FPo7yagSLthA==

The above result is not what I want, I expect ZJfsFFLjl6YS0Xys5OUVIA== to be the encrypted value of System.

Like the flowing Test On : http://aesencryption.net/

Any propositions?

Where does the two lines Output Comes from, i can only see 1 `System.out.println() — Jens, Aug 29 '17 at 10:17
click on encrypt button one more time, you will see a different result — Sachin Gupta, Aug 29 '17 at 10:20
You do notice that your Java code is using a random IV, whereas the online version is not using an IV at all? — Kayaman, Aug 29 '17 at 10:34
https://stackoverflow.com/users/2541560/kayaman, work for me after removing random IV, thanks for yur solution — zebiri djallil, Aug 29 '17 at 10:50
@Kayaman how do i accept your solution since it's a comment ? — zebiri djallil, Aug 29 '17 at 12:53

score 1 · Accepted Answer · answered Aug 29 '17 at 12:55

Your Java code is using an IV, while the web based encryption is not using one. For secure purposes, you should use a random IV so that encrypting the same data twice with the same key doesn't result in the same ciphertext. But if your requirement is to get the same result as from the web based one, leave out the initialization vector completely.

Encryption AES 128 with 2 different Result

1 Answers1