Need help in nested if in php

Question

I,i have this array which define each number it's color

$zero =  array(0=>"Empty",1=>"Red");
$red =   array(3=>"Red",5=>"Red",7=>"Red",9=>"Red",12=>"Red",14=>"Red",16=>"Red",21=>"Red",23=>"Red",25=>"Red",27=>"Red",30=>"Red",32=>"Red",34=>"Red",36=>"Red");
$black = array(2=>"Black",4=>"Black",6=>"Black",8=>"Black",10=>"Black",11=>"Black",13=>"Black",15=>"Black",17=>"Black",22=>"Black",24=>"Black",29=>"Black",31=>"Black",33=>"Black",35=>"Black");

$spin_numbers =array_merge($zero,$red,$black);

and I have form,which ask for number to bet,and it's start choosing random number between 0 and 36

if (isset($_POST['odd']))
{
  $random_number = mt_rand(0,36);
  if ($random_number == 1 OR $random_number == 3 OR $random_number == 5 OR $random_number == 7 OR $random_number == 9 OR $random_number == 11 OR $random_number == 13 OR $random_number == 15 OR $random_number == 17 OR $random_number == 19 OR $random_number == 21)
  {
    echo $random_number." ".$roulette_numbers[$random_number]." Occured,you won!";
  }
  else if ($random_number == 23 OR $random_number == 25 OR $random_number == 27 OR $random_number == 29 OR $random_number == 31 OR $random_number == 33 OR $random_number == 35)
  {
    echo $random_number." ".$roulette_numbers[$random_number]." Occured,you won!";
  }

  else if($random_number == 2 OR $random_number == 4 OR $random_number == 6 OR $random_number == 8 OR $random_number == 10 OR $random_number == 12 OR $random_number == 14 OR $random_number == 16 OR $random_number == 18 OR $random_number == 20 OR $random_number == 22)
    {
      "Sorry,".$random_number."Occured,your stake goes to Roulette";
    }
    else if ($random_number == 24 OR $random_number == 26 OR $random_number == 28 OR $random_number == 30 OR $random_number == 32 OR $random_number == 34 OR $random_number == 36)
    {
      "Sorry,".$random_number."Occured,your stake goes to Roulette";
    }

}

I want Odd numbers which most of them is Red,echo Win Message,and the rest numbers which is Even,echo loose Message,but it's only echo win Message,why?

furkanali89 · Answer 1 · 2018-04-01T09:20:20.427

1

Use echo with message.

echo "Sorry,".$random_number."Occured,your stake goes to Roulette"; echo "Sorry,".$random_number."Occured,your stake goes to Roulette";

edited Apr 01 '18 at 09:20

answered Mar 31 '18 at 16:29

furkanali89

150
4
14

i tried this before,not worked,i want also to echo it's color not only the random number – Aqil Mar 31 '18 at 16:33
sorry,i thought i'm using echo,really sorry bro,your answer was also the solution,i dont know why i didn't realize... – Aqil Mar 31 '18 at 17:08

score 1 · Accepted Answer · answered Mar 31 '18 at 16:40

1

I looks like you forgot the echo statement for the 2 even lines.

echo "Sorry,".$random_number."Occured,your stake goes to Roulette";

When you are developing you want to set your php.ini to show error and show all, including Notices.

You would have gotten an Notice: Notice: Undefined variable: roulette_numbers in [...][...] on line 19

Here is a good reference: How do I get PHP errors to display?

answered Mar 31 '18 at 16:40

PaulV

129
3

what a fool i am,how did i missed that,im really mixed up and tired that's why,anyway thank you... – Aqil Mar 31 '18 at 16:49

score 0 · Answer 3 · answered Mar 31 '18 at 16:34

0

Your code is working I was check it in browser. In your code you just need to echo message which is missed in your code. Your code is working use echo for displaying message.

answered Mar 31 '18 at 16:34

Devendra Choudhary

32
7

I think this is helpfull for you. – Devendra Choudhary Mar 31 '18 at 16:36

Need help in nested if in php

3 Answers3