How to Get the Target Folder

Question

I was just at Open directory dialog, and they said "get this package, and do this and this to get a folder select window to show up". Well, that all works great, using the Windows API Code Pack-Shell package. However, now I want to get the actual folder that is selected. I didn't notice them mentioning this anywhere.

I tried to do string folderLocation = Convert.ToString(dialog); (dialog is the variable for opening the folder window), but that only gave me like the property of the variable. I also tried this: CommonFileDialogResult result = dialog.ShowDialog(); string folderLocation = Convert.ToString(result);

But that just gave me "Ok" - which I take it is the result of it, instead of the actual folder.

If you had read the answers in that question, you would have found the answer to your question. You need to be a little bit persistent with these things. — 15ee8f99-57ff-4f92-890c-b56153, Jun 01 '18 at 13:49
Possible duplicate of [Open directory dialog](https://stackoverflow.com/questions/1922204/open-directory-dialog) — matt, Jun 01 '18 at 14:19

score 0 · Accepted Answer · answered Jun 01 '18 at 13:38

The result of ShowDialog just indicates wether the user clicked OK, cancel, or just closed the window. CommonOpenFileDialog can be used for both files and folders, so it's a bit surprising when used as a folder picker, but the path is stored in FileName.

var dlg = new CommonOpenFileDialog();
dlg.IsFolderPicker = true;
if(dlg.ShowDialog() == CommonFileDialogResult.Ok) {
    Console.WriteLine(dlg.FileName);
}

score 0 · Answer 2 · answered Jun 01 '18 at 13:59

If I understood correctly, you want to get Folder for a selected file? If that's the case, you can take FileInfo for that file, and extract folfer from it. Like this:

System.IO.FileInfo fInfo = new System.IO.FileInfo(oFD1.FileName);
MessageBox.Show(fInfo.DirectoryName);

PS. oFD1 is OpenFileDialog

How to Get the Target Folder

2 Answers2