why Storing multiple variables is creating a tuple

Question

Hi i am writing a code but unfortunately when i try to store multiple variables from a list or tuple into a new variable it just makes a new tuple

content=['2.0', 'Banana']
newli = content[0],'\t',content[1]
print(newli)

It should be printing like a string but it is printing as a tuple in round brackets. I need this tab spacing in between these two variables. Any help would be really appreciated.

by doing content[0]+'\t'+content[1] the tab space is not working

Actually what i wanted to achieve it so i can call this variable anywhere without using the manual print command everywhere and also to write in a file

Possible duplicate of [Concatenate item in list to strings](https://stackoverflow.com/questions/12453580/concatenate-item-in-list-to-strings) — Georgy, Jun 29 '18 at 08:38

score 2 · Answer 1 · answered Jun 29 '18 at 08:39

2

Replace the commas with + i.e.

newli = content[0] + '\t' + content[1]

answered Jun 29 '18 at 08:39

jc1850

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by doing this the tab space is not coming – Noob Saibot Jun 29 '18 at 08:42
When I run it the tab is there. – jc1850 Jun 29 '18 at 08:45
Its strange when i check on repl.it space it coming but not in my pycharm – Noob Saibot Jun 29 '18 at 08:47
Your pycharm console might be rendering the tab as 0 spaces, you could replace `'\t'` with `4*' '` to make sure it works on all consoles. – jc1850 Jun 29 '18 at 08:54

score 2 · Answer 2 · answered Jun 29 '18 at 08:39

2

You are not using string concatenation, but creating a tuple. You use , separation to create a tuple. You need to use + to concatenate strings.

content=['2.0', 'Banana']
newli = content[0] + '\t' + content[1]
print(newli)

answered Jun 29 '18 at 08:39

AndrejH

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by doing this the tab space is not coming – Noob Saibot Jun 29 '18 at 08:42

score 1 · Answer 3 · answered Jun 29 '18 at 08:39

1

newli is a tuple, since you're grouping values with a comma.

You should make it a string by doing this:

content=['2.0', 'Banana']
newli = content[0] + '\t' + content[1]
print(newli)

answered Jun 29 '18 at 08:39

magicleon94

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score 1 · Answer 4 · answered Jun 29 '18 at 08:39

This is normal behavior:

a = 'first', '\t', 'second' creates a tuple containing 'first', and tab and 'second'
a = 'first', creates a tuple containing 'first'; it is the comma that makes the tuple.

If you want to concatenate the values as a string, you could do like this:

a = 'first' + '\t' + 'second'

or like this, using f-strings:

f = 'first'
m = '\t'
s = 'second'
a = f'{f}{m}{s}'

score 0 · Answer 5 · answered Jun 29 '18 at 08:40

0

Its because you are asking for newli to store items as a tuple. Use string concatenation if you want to store them as a string

answered Jun 29 '18 at 08:40

sjaymj62

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score 0 · Answer 6 · answered Jun 29 '18 at 08:40

0

Yeah that's because you are putting comas between the strings. In python string concatenation is done with the + operator.

Try changing your code to:

content=['2.0', 'Banana']
newli = content[0] + '\t' + content[1]
print(newli)

answered Jun 29 '18 at 08:40

Zuma

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by doing this the tab space is not coming – Noob Saibot Jun 29 '18 at 08:41

score 0 · Answer 7 · answered Jun 29 '18 at 08:41

In Python values that are separated by comma (,) produces a tuple of that values. Like:

a=10
b=5
total_data = a,b
print(total_data) #this will produce a tuple (10, 5)

To get output as string you need to use + operator:

content=['2.0', 'Banana']
newli = content[0]+'\t'+content[1]
print(newli) #output: 2.0   Banana

Also you can use join function to get your expected output. Like:

content=['2.0', 'Banana']
newli = content[0],content[1]
print("\t".join(newli)) #output: 2.0   Banana

why Storing multiple variables is creating a tuple

7 Answers7