I would like to enlarge (=add new index to) a MultiIndex DataFrame by appending another DataFrame.
Here are the two DataFrames :
DF1 - pop :
mi = pd.MultiIndex.from_tuples([('in','a'),('in','b'),('v','t')],names=['Scope','Name'])
mc = pd.MultiIndex.from_tuples([(0,1),(0,2),(0,3)],names=['Gen','N'])
pop = pd.DataFrame([[1,2,3],[4,5,6],[7,8,9]],index=mi,columns=mc)
which gives:
Gen 0
N 1 2 3
Scope Name
in a 1 2 3
b 4 5 6
v t 7 8 9
DF2 - res :
mi = pd.MultiIndex.from_tuples([('in','a'),('in','b'),('res','c'),('res','d')],names=['Scope','Name'])
res = pd.DataFrame([[1,2,3],[4,5,6],[10,20,30],[11,22,33]],index=mi,columns=[1,2,3])
which gives:
1 2 3
Scope Name
in a 1 2 3
b 4 5 6
res c 10 20 30
d 11 22 33
I want to add the 'res' of res (sorry for bad naming...) to pop (where 'res' index still does not exist). I tried the followings with no success :
pop[0].loc['res'] = res['res']
pop.loc['res',0] = res['res']
Both leading to KeyError: 'res'
. I also tested something with pd.concat or append but with poor results (and I would like to not define a new DataFrame but to enlarge the original pop).
Thanks in advance for help.
WORKAROUND
I succeded in obtening the DataFrame I want, but not 'inplace' :
mi_col = pd.concat([res.loc['res']],keys=[0],axis=1) #Select 'res' index and add the '0' level to column
mi_ind = pd.concat([mi_col],keys=['res']) #Re-adding the 'res' level to index (drop during the previous selection)
pop = pd.concat([pop, mi_ind]) #Concatenating the 2 DataFrame into a new one
I am still interested in a solution that does not generate a new DataFrame.