How to find open ports on localhost using telnetlib python?

Question

I want to find all the ports that are open on my localhost using telnet. I have set up a server using sockets on port 1234. I am using the following code to check whether a port is open or not

import getpass
import sys
import telnetlib

HOST = "127.0.0.1"
for port in range (1,65535):
    try:
        if(telnetlib.Telnet(HOST,port)):
            print(port)
    except ConnectionRefusedError as err:
        print("connection refused")

However I get no output when I run this code. Appreciate any corrections in the code.Thanks

yes thank you i have corrected this small mistake.However the problem still persists I am trying to telnet to each port on the IP to find which ports are open. — Anuj Kulkarni, Jan 15 '19 at 20:17
That's wierd, it works for me. I just needed to remove this nasty "print("connection refused")" which was spamming nonsense (I replaced it with "pass"), now I see only open ports ;) — Damian, Jan 15 '19 at 20:21
Ok it seems to be working now. I just restarted sublime text and it worked.Thanks — Anuj Kulkarni, Jan 15 '19 at 21:09

score 1 · Answer 1 · answered Jan 15 '19 at 19:54

1

Arguments passed to a function should be delimited by a comma, not a dash:

for port in range(1, 65536):

answered Jan 15 '19 at 19:54

blhsing

91,368
6
71
106

score 0 · Answer 2 · answered Mar 15 '21 at 18:44

0

Modify the exception handling line without assigning the exception to a variable such below.

except ConnectionRefusedError:
        print("connection refused")

It worked for me without any error.

answered Mar 15 '21 at 18:44

iftekher2283

41
4

How to find open ports on localhost using telnetlib python?

2 Answers2