How can I use a function after using fetch with a return?
On the onchange event, I've placed an alert but that doesn't run. After the page is refreshed with fetch.
<select name="Request_keuzen" id="request_keuzen" class="form form-control" onchange="update_request_keuze_1(this.value)">
<option value="<?php echo $request_keuze_1 ?>"><?php echo $request_keuze_1 ?></option>
<?php
while ($row5 = mysqli_fetch_assoc($result5)):; ?>
<option value="<?php echo $row5['naam']; ?>"><?php echo $row5['naam']; ?></option>
<?php endwhile; ?>
</select>
function iso_nummer_content(isonumer) {
const data = new FormData();
let lisl_lijst_nummer = document.getElementById("lisl_lijst_nummer").value;
data.set("lisl_lijst_nummer", lisl_lijst_nummer);
data.set("isonummer", isonumer);
fetch("Fill_lisl_list2_items.php", {method: 'POST', body: data})
.then(response => response.text())
.then(tekst => document.getElementById("scriptophalen").innerHTML = tekst);
}
function update_request_keuze_1(str) {
const data = new FormData();
let selection = str;
let id = document.getElementById("id").value;
data.set("request_keuze_1", selection);
data.set("id", id);
fetch("Update_lisl_list_item_request_keuze_1.php", {method: 'POST', body: data})
}
Expected results:
After using fetch and my page is reloaded I can still use my function update_request_keuze_1.
FIXED WITH:
function update_request_keuze_1() {
var table = document.getElementById('tabel_lisl_lijst_fase_2');
for (var i = 1; i < table.rows.length; i++) {
table.rows[i].onclick = function () {
let id = this.cells[1].innerHTML;
let selection = this.cells[18].children[0].value;
const data = new FormData();
data.set("request_keuze_1", selection);
data.set("id", id);
fetch("Update_lisl_list_item_request_keuze_1.php", {method: 'POST', body: data})
}
}
}