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I am making a GUI with Tkinter and need to know which frame is on top so one of the lowered ones does not enter one of its loop and changes some settings.

I have already tried with

self.tk.eval('frame stackorder '+str(self.frames["StartPage"])+' isabove '+str(self.frames["Wallpaper"]))=='1'

self being my root (its a class) and get this error

_tkinter.TclError: bad window path name "stackorder"

also 

self.tk.eval('wm stackorder '+str(self.frames["StartPage"])

gives me the this error:

_tkinter.TclError: window ".!frame.!startpage" isn't a top-level window

This is the way I create and change between frames

self.frames = {}
        for F in (StartPage, PageOne, PageTwo):
            page_name = F.__name__
            frame = F(parent=container, controller=self)
            self.frames[page_name] = frame

            # put all of the pages in the same location;
            # the one on the top of the stacking order
            # will be the one that is visible.
            frame.grid(row=0, column=0, sticky="nsew")

        self.show_frame("StartPage")

    def show_frame(self, page_name):
        '''Show a frame for the given page name'''
        frame = self.frames[page_name]
        frame.tkraise()

I took the way to change frame from here (Switch between two frames in tkinter) but dont know how to know which one is on top.

Rudolf Fanchini
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1 Answers1

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You should probably keep a reference to the visible frame, so you can access it:

class App(tk.Tk()):
    def __init__(self, ...):
        ...
        self.visible_frame = "StartPage"
        ...

    def show_frame(self, page_name):
        '''Show a frame for the given page name'''
        frame = self.frames[page_name]
        frame.tkraise()
        self.visible_frame = page_name
Reblochon Masque
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