web scraping for javascript __doPostBack contain a herf in td

Question

I want to scrape a website i.e. is https://www.unspsc.org/search-code/default.aspx?CSS=51%&Type=desc&SS%27= using selenium but I am able to scrape only one page not other pages.

Here I am using selenium

from selenium import webdriver
from selenium.webdriver.chrome.options import Options
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

chromeOptions = webdriver.ChromeOptions()
chromeOptions.add_experimental_option('useAutomationExtension', False)
driver = webdriver.Chrome(executable_path='C:/Users/ptiwar34/Documents/chromedriver.exe', chrome_options=chromeOptions, desired_capabilities=chromeOptions.to_capabilities())
driver.get('https://www.unspsc.org/search-code/default.aspx?CSS=51%&Type=desc&SS%27=')
WebDriverWait(driver, 20).until(EC.staleness_of(driver.find_element_by_xpath("//td/a[text()='2']")))
driver.find_element_by_xpath("//td/a[text()='2']").click()

numLinks = len(WebDriverWait(driver, 20).until(EC.visibility_of_all_elements_located((By.XPATH, "//td/a[text()='2']"))))
print(numLinks)
for i in range(numLinks):
    print("Perform your scraping here on page {}".format(str(i+1)))
    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//td/a[text()='2']/span//following::span[1]"))).click()
driver.quit()

here is the html content

    <td><span>1</span></td>
    <td><a 
     href="javascript:__doPostBack 
(&#39;dnn$ctr1535$UNSPSCSearch$gvDetailsSearchView&#39;,&#39;Page$2&#39;)" 
style="color:#333333;">2</a>
     </td>

This throws an error:

raise TimeoutException(message, screen, stacktrace)
TimeoutException

Answer 1

To scrape the website https://www.unspsc.org/search-code/default.aspx?CSS=51%&Type=desc&SS%27= using Selenium you can use the following Locator Strategy:

• Code Block:

    from selenium import webdriver
    from selenium.webdriver.support.ui import WebDriverWait
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support import expected_conditions as EC
  
    chrome_options = webdriver.ChromeOptions() 
    chrome_options.add_argument("start-maximized")
    driver = webdriver.Chrome(options=chrome_options, executable_path=r'C:\WebDrivers\chromedriver.exe')
    driver.get("https://www.unspsc.org/search-code/default.aspx?CSS=51%&Type=desc&SS%27=%27")
    while True:
        try:
            WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.XPATH, "//table[contains(@id, 'UNSPSCSearch_gvDetailsSearchView')]//tr[last()]//table//span//following::a[1]"))).click()
            print("Clicked for next page")
        except TimeoutException:
            print("No more pages")
            break
    driver.quit()
  

• Console Output:

    Clicked for next page
    Clicked for next page
    Clicked for next page
    .
    .
    .
  

• Explaination: If you observe the HTML DOM the page numbers are within a <table> with a dynamic id attribute containing the text UNSPSCSearch_gvDetailsSearchView. Further the page numbers are within the last <tr> which is having a child <table>. With in the child table the current page number is within a <span> which holds the key. So to click() on the next page number you just need to identify the following <a> tag with index [1]. Finally, as the element is having javascript:__doPostBack() you have to induce WebDriverWait for the desired element_to_be_clickable().

You can find a detailed discussion in How do I wait for a JavaScript __doPostBack call through Selenium and WebDriver

Answer 2

To find/click the page numbers you can use:

for x in driver.find_elements_by_xpath("//a[contains(@href,'UNSPSCSearch$gvDetailsSearchView')]"):
    if x.text.isdigit():
        print(x.text)
        #x.click()
        #...

---

Output:

2
3
4
...

---

Based on your comment, you can use:

max_pages = 10
for page_number in range(2, max_pages+1):
    for x in driver.find_elements_by_xpath("//a[contains(@href,'UNSPSCSearch$gvDetailsSearchView')]"):
        if x.text.isdigit():
            if int(x.strip()) == page_number:
                x.click()
                #parse results here
                break