I am investigating some problem with a local binary. I've noticed that g++ creates a lot of ASM output that seems unnecessary to me. Example with -O0
:
Derived::Derived():
pushq %rbp
movq %rsp, %rbp
subq $16, %rsp <--- just need 8 bytes for the movq to -8(%rbp), why -16?
movq %rdi, -8(%rbp)
movq -8(%rbp), %rax
movq %rax, %rdi <--- now we have moved rdi onto itself.
call Base::Base()
leaq 16+vtable for Derived(%rip), %rdx
movq -8(%rbp), %rax <--- effectively %edi, does not point into this area of the stack
movq %rdx, (%rax) <--- thus this wont change -8(%rbp)
movq -8(%rbp), %rax <--- so this statement is unnecessary
movl $4712, 12(%rax)
nop
leave
ret
option -O1 -fno-inline -fno-elide-constructors -fno-omit-frame-pointer
:
Derived::Derived():
pushq %rbp
movq %rsp, %rbp
pushq %rbx
subq $8, %rsp <--- reserve some stack space and never use it.
movq %rdi, %rbx
call Base::Base()
leaq 16+vtable for Derived(%rip), %rax
movq %rax, (%rbx)
movl $4712, 12(%rbx)
addq $8, %rsp <--- release unused stack space.
popq %rbx
popq %rbp
ret
This code is for the constructor of Derived
that calls the Base
base constructor and then overrides the vtable pointer at position 0 and sets a constant value to an int member it holds in addition to what Base
contains.
Question:
- Can I translate my program with as few optimizations as possible and get rid of such stuff? Which options would I have to set? Or is there a reason the compiler cannot detect these cases with
-O0
or-O1
and there is no way around them? - Why is the
subq $8, %rsp
statement generated at all? You cannot optimize in or out a statement that makes no sense to begin with. Why does the compiler generate it then? The register allocation algorithm should never, even with O0, generate code for something that is not there. So why it is done?