Pointer inside a square bracket?

Question

Consider the following code:

#include <stdio.h>
int main(void){
    char *p="A for Apple";
    char q[15]="B for Ball";
    printf("x=%c y=%c\n",*(p+10)-2,*(&q[4]-2)); 
    printf("u=%c v=%c w=%d\n",p[8],*q+8,8[p]-q[8]);
    return 0;
}

Output:

x=c y=f  
u=p v=J
w=4

Problem, I am having here is determining how w=4 was evaluated.

What does 8[p] means?

It means the same as `p[8]`. – Weather Vane Oct 30 '19 at 23:10 — Weather Vane, Oct 30 '19 at 23:10

score 3 · Accepted Answer · answered Oct 30 '19 at 23:13

3

a[x] is shorthand for *(a + x). Consequently, a[x] is equivalent to the expression x[a]. (same holds for 8[p] and p[8] of course ;))

answered Oct 30 '19 at 23:13

knittl

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Pointer inside a square bracket?

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