How to get pretty formatted output from RestTemplate?

Question

Below is my response from one of the server call from my Spring Boot app,

String result = restTemplate.exchange(url, HttpMethod.GET, entity, String.class).getBody();

Then I am returning to client like,

return ResponseEntity.ok().body(result);

In postman I see json is printed with many \" rather pretty formated.

Is there I need to change in response side to see pretty formatted output in Postman?

Sample Postman output:

"{\"records\":[{\"pkg_name\":\"com.company.app\",\"start_time\":1580307656040,\"update_time\":12345,\"min\":0.0,\"create_time\":1580307714254,\"time_offset\":21600000,\"datauuid\":\"xyz\",\"max\":0.0,\"heart_beat_count\":1,\"end_time\":1580307656040,\"heart_rate\":91.0,\"deviceuuid\":\"abc\"}]}" ...

Expected output: Pretty formatted without \"

https://stackoverflow.com/questions/6541757/when-using-spring-mvc-for-rest-how-do-you-enable-jackson-to-pretty-print-render — pvpkiran, Mar 20 '20 at 08:18
@pvpkiran actually I want to remove `\"` how to do so? Updated the post. — Sazzad Hissain Khan, Mar 20 '20 at 08:19

Nonika · Accepted Answer · 2020-03-20T09:32:38.650

1

It seems to me that String result = restTemplate.exchange(url, HttpMethod.GET, entity, String.class).getBody(); returns double encoded json string. to unescape and get normal json

 String unwrappedJSON = objectMapper.readValue(result, String.class);
 return ResponseEntity.ok().body(unwrappedJSON);

EDIT

if result is normal json and not double escaped than you can try:

JsonNode result = restTemplate.exchange(url, HttpMethod.GET, entity, JsonNode.class).getBody();

return ResponseEntity.ok().body(result);

edited Mar 20 '20 at 09:32

answered Mar 20 '20 at 09:19

Nonika

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What is object mapper? – Sazzad Hissain Khan Mar 20 '20 at 09:21
just @Autowire it `@Autowired ObjectMapper objectMapper;` – Nonika Mar 20 '20 at 09:23
tried with `result = (new ObjectMapper()).readValue(result, String.class);` didn't help though – Sazzad Hissain Khan Mar 20 '20 at 09:24
can you print `result` before send – Nonika Mar 20 '20 at 09:24
before this line `return ResponseEntity.ok().body(result);` – Nonika Mar 20 '20 at 09:25
actually exception happened `com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of `java.lang.String` out of START_OBJECT token` – Sazzad Hissain Khan Mar 20 '20 at 09:25
Let us [continue this discussion in chat](https://chat.stackoverflow.com/rooms/209986/discussion-between-nonika-and-sazzad-hissain-khan). – Nonika Mar 20 '20 at 09:26

score 0 · Answer 2 · answered Mar 20 '20 at 08:22

0

The best approach is to create bean and deserializate this String to it. After it you will have structured object with all benefits. (For example pretty toString method)

answered Mar 20 '20 at 08:22

yazabara

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If you provide MWE it would be helpful – Sazzad Hissain Khan Mar 20 '20 at 08:32
What does mean MWE? Example? restTemplate.getForObject(url, request, Foo.class) – yazabara Mar 20 '20 at 08:39
ResponseEntity response = restTemplate .exchange(url, HttpMethod.GET, request, Foo.class); – yazabara Mar 20 '20 at 08:40

How to get pretty formatted output from RestTemplate?

2 Answers2