Error when creating file opening window by using tkinter library

Question

I am referring to this post: Tkinter not creating a window?. And the code published there as answer returns me the same error on my code: TclError: no display name and no $DISPLAY environment variable This is my code:

import tkinter
root = tkinter.Tk()
root.title = ('Project planner')
open_button = tkinter.Button(root, text='Open project...', command=open_project)
open_button.pack(side='top')
canvas = tkinter.Canvas(root, width=800, height=400, bg='white')
canvas.pack(side='bottom')
tkinter.mainloop()

What is wrong?

On Jupyther Notebook now here: [link](https://jupyter.org/try) I can try to run it and test it on Anaconda Spyder (this evening..) I believe this is the issue.. — wotesi, Jun 01 '20 at 09:34
Are you running this notebook on your local machine or on a server? — Anwarvic, Jun 01 '20 at 09:40
I believe it is on server. Well I am running it on local machine, but Jupyther Notebook is located on server. — wotesi, Jun 01 '20 at 10:12
No, this code works if you host the notebook on your machine. — Anwarvic, Jun 01 '20 at 10:18

score 0 · Accepted Answer · answered Jun 01 '20 at 18:28

0

I should be running my code locally, then it works, it does not work on server.

answered Jun 01 '20 at 18:28

wotesi

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Error when creating file opening window by using tkinter library

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