Django URL does not see the link and its POST request

Question

I made a project, but in it you need to get a special token from the VK social network. I made the token pass along with the link. She looks like this:

http://127.0.0.1:8000/vk/auth#access_token=7138dcd74f5da5e557943b955bbfbd9a62811da7874067e5fa0edef1ca8680216755be16&expires_in=86400&user_id=397697636

But the problem is that the django cannot see this link. I tried to look at it in a post request, get request, but everything is empty there. I tried to make it come not as a request but as a link, it is like this:

http://127.0.0.1:8000/vk/auth #access_token=7138dcd74f5da5e557943b955bbfbd9a62811da7874067e5fa0edef1ca8680216755be16&expires_in=86400&user_id=397697636

But the django does not want to read the space. Who can help

some code would help - but surely this is a query parameter, not a hash fragment, and therefore your `#` in the first URL should be a `?`? — Robin Zigmond, Jun 08 '20 at 20:12
the server sends this fragment: #access_token=7138dcd74f5da5e557943b955bbfbd9a62811da7874067e5fa0edef1ca8680216755be16&expires_in=86400&user_id=397697636 at the end of the link that I indicate: http://127.0.0.1:8000/vk/auth — , Jun 08 '20 at 20:15
If it is, then this is a link to the page where it is described how to get a token: https://vk.com/dev/implicit_flow_user — , Jun 08 '20 at 20:25

gelonida · Accepted Answer · 2020-06-08T21:31:13.170

I think there is a confusion between a query string (get params) that follows a ? and a fragment (the text, that follows a #)

What follows the # is not sent to the server (and thus not received by Django) it is only useful to the web browser and to the javascript that is executed on the browser , which can use it to update parts of the screen. use it as virtual urls / bookmarks for one page web applications. The javascript can of course also trigger AJAX requests using that data, but that's up to the javascript

If you write however http://127.0.0.1:8000/vk/auth?access_token=7138dcd74f5da5e557943b955bbfbd9a62811da7874067e5fa0edef1ca8680216755be16&expires_in=86400&user_id=397697636 (you replace # with ?)

Then you can receive the information in your django view with

request.GET["access_token"], request.GET["expires_in"] and request.GET["user_id"]

If it is really a #, then your javascript should parse whatever follows the # and make the according AJAX requests to the server to send / validate the token.

For another question about fragments, refer for example to Is the URL fragment identifier sent to the server?

Django URL does not see the link and its POST request

1 Answers1