List Comprehension - Conditional

Question

For these 2 lists:

A=['3.40', '4.00', '151.00', '8.00', '81.00', '23.00', '17.00', '8.50', '5.00', '151.00', 'SCR', 'SCR', '13.00']
B=['11', '5', '2', '4', '6', '9', '7', '8', '10', '1', '12', '10', '3']

The desired output is:

C=['11', '5', '2', '4', '6', '9', '7', '8', '10', '1', '3']

So - list 'A' and list 'B' are the same length. List 'C' is the same as list 'B' - but does not have the values where 'SCR' exists in list 'A'.

My attempt at this is:

C = [x for x in B if x in A!='SCR']

Thankyou

`c = [b for a, b in zip(A, B) if a != "SCR]` – Paul M. Sep 13 '20 at 19:16 — Paul M., Sep 13 '20 at 19:16

score 4 · Accepted Answer · answered Sep 13 '20 at 19:16

4

just zip them together:

C = [b for a,b in zip(A,B) if a != 'SCR']

answered Sep 13 '20 at 19:16

GalSuchetzky

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score 1 · Answer 2 · answered Sep 13 '20 at 19:16

1

Based on what I think you're trying to accomplish, I think you would need this:

C = [B[x] for x in range(len(B)) if A[x] != 'SCR']

answered Sep 13 '20 at 19:16

Llama Boy

103
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May be worth reading: [Never use "for i in range(len(sequence))](https://python-forum.io/Thread-Basic-Never-use-for-i-in-range-len-sequence) and [Loop like a native](https://nedbatchelder.com/text/iter.html) – jarmod Sep 13 '20 at 19:20

Robin Zigmond · Answer 3 · 2020-09-14T07:32:13.043

1

This is straightforward using the built-in enumerate function:

[x for (idx, x) in enumerate(B) if A[idx] == 'SCR']

edited Sep 14 '20 at 07:32

answered Sep 13 '20 at 19:17

Robin Zigmond

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List Comprehension - Conditional

3 Answers3