How do I generate random dark colors in C#?

Question

I generate a random color this way:

 var random = new Random();
 var color = String.Format("#{0:X6}", random.Next(0x1000000));

How can I exclude colors brighter than a certain value?

I know it's old question. In case someone needs, check this answer. https://stackoverflow.com/a/56848413/2417445 — Krish, Jul 02 '19 at 08:36

score 12 · Accepted Answer · answered Jun 18 '11 at 13:14

12

An quite simple way to get rid of the "upper half" of brightes colors is to mask the result via

random.Next(0x1000000) & 0x7F7F7F

answered Jun 18 '11 at 13:14

Howard

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if you do `string.Format("#{0:x}",random.Next(0x1000000) & 0x7F7F7F);` in some cases result will be 5 hexadecimal numbers. Do not forget x6 format. – nerijus Oct 08 '13 at 12:50
What happened here? Can you link to some documentation? – Piotrek May 30 '15 at 11:23
What if i want to get rid of dark colors, and keep the bright ones!? – Joe May 08 '23 at 02:42

score 7 · Answer 2 · answered Jun 18 '11 at 13:07

7

One way to do this is to generate colours in the HSV/HSL colour-space, and then convert to RGB (the Wikipedia article tells you how to do that).

The advantage of HSV is that one of the components (V) corresponds to "brightness". So if you generate H, S and V independently and randomly, but restrict V to low values, then you will get dark colours.

answered Jun 18 '11 at 13:07

Oliver Charlesworth

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here is a [link](http://www.splinter.com.au/converting-hsv-to-rgb-colour-using-c/) on how to do the conversion in c# – Heribert Jun 19 '15 at 07:33

score 0 · Answer 3 · answered Sep 22 '20 at 04:25

0

You can install ColorHelper library via NuGet and use next code:

using ColorHelper;
RGB rgb = ColorGenerator.GetDarkRandomColor<RGB>();

Instead of RGB class you can use another. E.g.: HEX, CMYK or another.

answered Sep 22 '20 at 04:25

progm

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How do I generate random dark colors in C#?

3 Answers3

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