Regex to extract a number of any length from a string

Question

I am trying to extract a number (Must exist, any length) from a string. The string should actually start with the number. I am using this expression:

[[\d]+YMD]

When given 11M as input, the 11 is matched twice as 1 then 1. What am I missing in this RegEx?

I am writing a web application, but for now, I am testing the RegEx online where I am getting the same results.

Try `^\d+` if you want to retrieve the number at the start of your string — Aaron, Sep 23 '20 at 09:00
Or else use a capturing group or lookahead `^\d+(?=[YMD])` to get the digits only. — The fourth bird, Sep 23 '20 at 09:04

score 1 · Answer 1 · answered Sep 23 '20 at 09:00

1

I guess you want:

^\d+

^ = start of string \d = any digit + = 1 or more

answered Sep 23 '20 at 09:00

maio290

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score 1 · Accepted Answer · answered Sep 23 '20 at 09:01

You're most likely looking for the + quantifier which: "Matches between one and unlimited times, as many times as possible, giving back as needed".

^\d+(D|M|Y) will specifically give you what you seem to be looking for (making it only match if it starts with a number and ends with D, M, or Y, making sure there's at least 1 number.

https://regex101.com/r/gWxkhd/2

Regex to extract a number of any length from a string

2 Answers2