Seaborn chart in Jupyter notebook ignoring figsize parameter

Question

For some reason chart size remains unchanged, although I've changed figsize parameters. Very appreciate your help :)

import pandas as pd
import seaborn as sns
import matplotlib.pyplot as plt
dt = pd.DataFrame({'col':[26,0,23,7,23,23,22,23,19,22,1,1,11,11,23,14,23,21,11,23,10,11,13,28,18,25,23,28,18,23,18,18,
23,18,23,24,11,28,23,23,23,23,19,23,23,23,23,22,14]})


plt.figure(figsize=(15,6))
sns.displot(dt['col'], kde=True)
plt.show()

This is a result I get

distplot just makes a new figure for you. Try: `fig, ax = plt.subplots(figsize=(15, 6)); sns.displot(dt['col'], kde=True, ax=ax);` — Jody Klymak, Jun 15 '21 at 14:51

score 3 · Accepted Answer · answered Jun 15 '21 at 12:29

3

Try rewriting the code in this way:

g=sns.displot(dt['col'], kde=True)
g.fig.set_size_inches(15,6)

You can go through this for further information

answered Jun 15 '21 at 12:29

Mohammad Atif

216
1
4

score 1 · Answer 2 · answered Jun 15 '21 at 17:48

1

Try using the height parameter (in inches) and aspect (as the ratio of widht/height)

you want a figure with an aspect ratio of 2.67

ar = width / height 
ar = 16/6 
ar = 2.67

Try this line instead:

g=sns.displot(dt['col'], kde=True,height=6,aspect=2.67)

answered Jun 15 '21 at 17:48

DiegoRC

13
3

Thank you, it worked this way! I wander why regular figsize not working in this case? – Sergey Kuper Jun 17 '21 at 05:55

Seaborn chart in Jupyter notebook ignoring figsize parameter

2 Answers2