File py called function of another py file with Tkinter window: problem in changing icons and displaying error messages

Question

I'm having trouble linking B.py script functions in the MAIN.py graphics window. This is a test of Tkinter's graphics window to check if the scraping (for the purpose of my personal and didactic study) was successful or there were errors. B.py is the script (works fine, okay) for scraping and error detection, while MAIN.py is the graphical test window. I have problems with Main.py

I write in order the steps I would like to obtain. I wrote their code (below), but something is wrong. I think they are very simple, but I searched the web and couldn't solve:

1. I open the MAIN.py graphics window and click the Start button. The B.py file is executed
2. If the scraping was successful, the small blue image / icon "boh.png" is replaced with the green (ok) image contained in /home/mypc/Desktop/Folder/img/green.png
3. If the scraping was not successful and there is an error, I get the red icon contained in /home/mypc/Desktop/Folder/img/red.png which replaces the blue one.
4. In case of errors, besides the image replacement, I would like to display the related 3 error (expect 1, expect 2 or if records_added_Resultati == 0) instead of the label "Message"

ERROR and PROBLEMS: After scraping, the blue icon is not replaced by the red or green icon. Also, the error message (except 1, or expect 2, or if ....) is not displayed in the Messages label.

MAIN.PY (graphics window)

from tkinter import *
from tkinter import ttk
import tkinter as tk
import tkinter.font as tkFont
from PIL import ImageTk, Image
from File import B

def draw_graph():
    test_scraping=tk.Toplevel()
    test_scraping.title("Test")
    test_scraping.geometry("800x600")
    test_scraping.configure(bg='#282828')

testN1 = Label(test, text="TEST N.1", bg="#282828", foreground='white')
testN1.place(x=6, y=12)

image_blu= Image.open("/home/mypc/Desktop/Folder/File/img/blu.png")
render1 = ImageTk.PhotoImage(image_blu)
image_blu = Label(test, image=render1, bg='#282828')
image_blu.place(x=76, y=12)

message = Label(test, text="Message ", bg="#282828", foreground='white')
message.place(x=156, y=12)

    def do_scraping():
        msg = B.scraping()
        if msg:
            message.configure(text=msg)

            image_red= Image.open("/home/mypc/Desktop/Folder/File/img/error.png")
            render7 = ImageTk.PhotoImage(image_red)
            image_red = Label(test_scraping, image=render7, bg='#282828')
            image_red.place(x=400, y=12)

        else:
            image_green= Image.open("/home/mypc/Desktop/Folder/File/img/ok.png")
            render8 = ImageTk.PhotoImage(image_green)
            image_green = Label(test_scraping, image=render8, bg='#282828')
            image_green.place(x=400, y=12) 


button = Button(test, text="Avvia", bg='#e95420', foreground='white', command=do_scraping)
button.place(x=6, y=112)

test.mainloop()

B.PY

from tkinter import *
from tkinter import ttk
import tkinter as tk
import sqlite3
from selenium.common.exceptions import NoSuchElementException

def scraping:
    #Code Tor Connection. Useless to write it down. not important for the purposes of the example 

    try:
        #Serie A
        driver.get("link")
        driver.close
        SerieA=driver.find_element_by_class_name("teamHeader__name")
        SerieA_text = SerieA.text
        print(SerieA.text)

        #Serie B
        driver.get("link")
        driver.close
        SerieB=driver.find_element_by_class_name("teamHeader__name")
        SerieB_text = SerieB.text
        print(SerieB.text)

    except NoSuchElementException:
        return "FAILED: Error class name html"

    except ValueError:
        return "FAILED: Error ValueError"

    if records_added_Risultati == 0:
       raise ValueError("FAILED: 0 record scraping")


#Code for insert in database

Answer 1

You hadn't actually placed label in right place. You had place it in x=400 and I think that's the reason you are not seeing that label(image) in right place. Try to change that label in x=76 where that blue image is located. And try to destroy blue image label before placing other label.

Edit1:

You can replace image doing :

from tkinter import *
from tkinter import ttk
import tkinter as tk
import tkinter.font as tkFont
from PIL import ImageTk, Image
from File import B

def draw_graph():
    test_scraping=tk.Toplevel()
    test_scraping.title("Test")
    test_scraping.geometry("800x600")
    test_scraping.configure(bg='#282828')

testN1 = Label(test, text="TEST N.1", bg="#282828", foreground='white')
testN1.place(x=6, y=12)

image_blu= Image.open("/home/mypc/Desktop/Folder/File/img/blu.png")
render1 = ImageTk.PhotoImage(image_blu)
image_blu = Label(test, image=render1)
image_blu.place(x=76, y=12)

message = Label(test, text="Message ", bg="#282828", foreground='white')
message.place(x=156, y=12)

image_green= Image.open("/home/mypc/Desktop/Folder/File/img/ok.png")
render8 = ImageTk.PhotoImage(image_green)

image_red= Image.open("/home/mypc/Desktop/Folder/File/img/error.png")
render7 = ImageTk.PhotoImage(image_red)
            
def do_scraping():
        msg = B.scraping()
        if msg:
            message.configure(text=msg)
            image_blu.config(image=render7)
        else:
            image_blu.config(image=render8)

button = Button(test, text="Avvia", bg='#e95420', foreground='white', command=do_scraping)
button.place(x=6, y=112)

test.mainloop()

Instead of making new label/image. Replacing that existing label will be efficient.

Edit2:

records_added_Risultati == 0 if this condition is true then, there is no way. User can know what is going on without looking on terminal. So, It should return something, so that user will get the red icon and know, scraping was not successful.

from tkinter import *
from tkinter import ttk
import tkinter as tk
import sqlite3
from selenium.common.exceptions import NoSuchElementException

def scraping:
    #Code Tor Connection. Useless to write it down. not important for the purposes of the example 

    try:
        #Serie A
        driver.get("link")
        driver.close
        SerieA=driver.find_element_by_class_name("teamHeader__name")
        SerieA_text = SerieA.text
        print(SerieA.text)

        #Serie B
        driver.get("link")
        driver.close
        SerieB=driver.find_element_by_class_name("teamHeader__name")
        SerieB_text = SerieB.text
        print(SerieB.text)

    except NoSuchElementException:
        return "FAILED: Error class name html"

    except ValueError:
        return "FAILED: Error ValueError"

    if records_added_Risultati == 0:
       return "FAILED: 0 record scraping"