I'm trying to program an interface with tkinter, that shows users of my application as a list of Labels. The list is created from a database (created with sqlite3). By clicking on each Label the program should open another window, showing details of the clicked user. maybe do I need to use classes? (because for now, my script is not OOP)
root = Tk()
root.title("Utenti")
root.iconbitmap("D:\Willow\WilloW SW Gestionale")
root.geometry("365x600")
def open_user(name = str):
user = Tk()
user.title("Utenti")
user.iconbitmap("D:\Willow\WilloW SW Gestionale")
user.geometry("500x400")
#create entry
f_name_entry = Entry(user, width=30, state="disabled")
f_name_entry.grid(row=0, column=1, padx=20, pady=(10, 0))
P_iva_entry = Entry(user, width=30, state="disabled")
P_iva_entry.grid(row=1, column=1)
cell_number_entry = Entry(user, width=30, state="disabled")
cell_number_entry.grid(row=2, column=1)
tax_entry = Entry(user, width=30, state="disabled")
tax_entry.grid(row=3, column=1)
inps_entry = Entry(user, width=30, state="disabled")
inps_entry.grid(row=4, column=1)
# create text boxes
f_name_label = Label(user, text=name)
f_name_label.grid(row=0, column=0, pady=(10, 0))
P_iva_label = Label(user, text="p iva")
P_iva_label.grid(row=1, column=0)
cell_number_label = Label(user, text="cell number")
cell_number_label.grid(row=2, column=0)
tax_label = Label(user, text="tax")
tax_label.grid(row=3, column=0)
inps_label = Label(user, text="inps")
inps_label.grid(row=4, column=0)
i = 4
conn = sqlite3.connect("usersEsteso.db")
c = conn.cursor()
c.execute("SELECT *, oid FROM usersEsteso")
records = c.fetchall()
for record in records:
print_records = record[0]
users_lable = Label(root, bg="#778899")
users_lable.grid(row=i + 7, column=0, sticky="w", padx=5, pady=5, columnspan=3)
user_text = Label(users_lable, text=print_records)
user_text.grid(row=0, column=0, pady=5, padx=5, sticky="w")
#user_text.bind("<Enter>", open_user("sam"))
openUser_lable_button = Button(users_lable, text="apri " + record[0], command=lambda: open_user(record[0])) #here i showld pass the identification of the parent the button
openUser_lable_button.grid(row=1, column=0, pady=5, padx=5, sticky="e")
i = i + 1
conn.commit()
conn.close()