If you're looking for a complete Python Selenium solution for solving the Wordle Game programmatically, here's one that uses the SeleniumBase framework. The solution comes with a YouTube video: Solving Wordle using SeleniumBase, as well as the Python code of the solution, and a GIF of what to expect:
The code uses special SeleniumBase ::shadow
selectors in order to pierce through multiple layers of Shadow-DOM. Here's the code below, which can be run after calling pip install seleniumbase
to get all the Python dependencies:
import ast
import random
import requests
from seleniumbase import __version__
from seleniumbase import BaseCase
class WordleTests(BaseCase):
word_list = []
def initalize_word_list(self):
js_file = "https://www.powerlanguage.co.uk/wordle/main.e65ce0a5.js"
req_text = requests.get(js_file).text
start = req_text.find("var La=") + len("var La=")
end = req_text.find("],", start) + 1
word_string = req_text[start:end]
self.word_list = ast.literal_eval(word_string)
def modify_word_list(self, word, letter_status):
new_word_list = []
correct_letters = []
present_letters = []
for i in range(len(word)):
if letter_status[i] == "correct":
correct_letters.append(word[i])
for w in self.word_list:
if w[i] == word[i]:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
for i in range(len(word)):
if letter_status[i] == "present":
present_letters.append(word[i])
for w in self.word_list:
if word[i] in w and word[i] != w[i]:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
for i in range(len(word)):
if (
letter_status[i] == "absent"
and word[i] not in correct_letters
and word[i] not in present_letters
):
for w in self.word_list:
if word[i] not in w:
new_word_list.append(w)
self.word_list = new_word_list
new_word_list = []
def test_wordle(self):
self.open("https://www.powerlanguage.co.uk/wordle/")
self.click("game-app::shadow game-modal::shadow game-icon")
self.initalize_word_list()
keyboard_base = "game-app::shadow game-keyboard::shadow "
word = random.choice(self.word_list)
total_attempts = 0
success = False
for attempt in range(6):
total_attempts += 1
word = random.choice(self.word_list)
letters = []
for letter in word:
letters.append(letter)
button = 'button[data-key="%s"]' % letter
self.click(keyboard_base + button)
button = 'button[data-key="↵"]'
self.click(keyboard_base + button)
self.sleep(1) # Time for the animation
row = 'game-app::shadow game-row[letters="%s"]::shadow ' % word
tile = row + "game-tile:nth-of-type(%s)"
letter_status = []
for i in range(1, 6):
letter_eval = self.get_attribute(tile % str(i), "evaluation")
letter_status.append(letter_eval)
if letter_status.count("correct") == 5:
success = True
break
self.word_list.remove(word)
self.modify_word_list(word, letter_status)
self.save_screenshot_to_logs()
print('\nWord: "%s"\nAttempts: %s' % (word.upper(), total_attempts))
if not success:
self.fail("Unable to solve for the correct word in 6 attempts!")
self.sleep(3)
This solution requires minimum SeleniumBase version 2.4.0
(or newer) due to updated Shadow-DOM methods. (Here are the Release Notes of that version.)
Note that SeleniumBase tests are run using pytest
. Also, the Wordle website appears slightly differently when opened using headless Chrome, so don't use Chrome's headless mode when running this example.