How to get the rest of the list from a subset of it

Question

a and b are lists of numbers and there are duplicates. b is a subset of a.

For example:

a = [1, 1, 1, 2, 2, 3]
b = [1, 1, 2]

I'm working on a function to get the rest of a after deleting the numbers in b:

>>> func(a, b)
[1, 2, 3]

I know it can be achived by enumerating through the list, but is there an easier way to get the result?

As far as we can tell you _aren't_ slicing anything (it wouldn't really make sense to do so). If you know how it can be achieved, where's your implementation? — jonrsharpe, Jun 07 '22 at 12:50
If func() returns a list simply save it to a new or existing variable, if it alters an existing variable you dont have to do anything? — Josip Juros, Jun 07 '22 at 12:51
after getting a combination by itertools, I also want to get the rest of it — sty331, Jun 07 '22 at 13:02

score -3 · Answer 1 · answered Jun 07 '22 at 12:53

-3

If you like to remove duplicates, just convert to to set:

nodups = set(a)

if you like it in LIST:

nodups = list(set(a))

answered Jun 07 '22 at 12:53

Avner Cohen

1

He doesnt want to remove duplicates, he wants to remove elements that are in the other list. – Josip Juros Jun 07 '22 at 12:54
According the result he expecting - this is what he like to do.. – Avner Cohen Jun 07 '22 at 12:57
Same result for this particular input, yes, but very different algorithm. – deceze Jun 07 '22 at 12:58
1

You could also `return [1, 2, 3]` which gives the same result but doesn't really make much sense. – alex Jun 07 '22 at 12:59

1 Answers1