Split this into two queries that you combine with UNION
.
The first joins the implicit
row with the row with the highest attendance among the explicit rows for each student. See Retrieving the last record in each group - MySQL for how that works. Use SUM(attendance_count)
to combine the attendances.
The second query in the UNION
gets all the rows that don't have the highest attendance.
WITH explicit as (
SELECT *
FROM school_temp
WHERE original_classification!='all' and availability!='implicit'
)
SELECT a.student_id, a.school_id, a.name, SUM(attendance_count) AS attendance_count,
b.grant, b.classification, b.original_classification, b.consent_type
FROM school_temp AS a
JOIN (
SELECT t1.*
FROM explicit AS t1
JOIN (
SELECT student_id, school_id, name, MAX(attendance_count) AS max_attendance
FROM explicit AS t2
GROUP BY student_id, school_id, name
) AS t2 ON t1.student_id = t2.student_id AND t1.school_id = t2.school_id AND t1.name = t2.name AND t1.attendance_count = t2.max_attendance
) AS b ON a.student_id = b.student_id and a.school_id=b.school_id and a.name=b.name
WHERE a.original_classication = 'all' AND a.availability = 'implicit'
UNION ALL
SELECT t1.*
FROM explicit AS t1
JOIN (
SELECT student_id, school_id, name, MAX(attendance_count) AS max_attendance
FROM explicit AS t2
GROUP BY student_id, school_id, name
) AS t2 ON t1.student_id = t2.student_id AND t1.school_id = t2.school_id AND t1.name = t2.name AND t1.attendance_count < t2.max_attendance
I've used a CTE to give a name to the subquery that gets all the explicit rows. If you're using MySQL 5.x, you'll need to replace explicit
with that subquery throughout the query. Or you could define it as a view.