I have referenced this question many times regarding how to render linked images in pandas data frame
And it is quite easy to implement. However, I have come across a scenario where I would like to render a local image in my current working directory in a pandas dataframe. I figured I could just replace the image link(s) in the snippet below (credit to @chitown88 with this code from the linked question) with the image path, but that doesn't appear to work.
import pandas as pd
from IPython.core.display import display,HTML
df = pd.DataFrame([['A231', 'Book', 5, 3, 150],
['M441', 'Magic Staff', 10, 7, 200]],
columns = ['Code', 'Name', 'Price', 'Net', 'Sales'])
# your images
images1 = ['https://vignette.wikia.nocookie.net/2007scape/images/7/7a/Mage%27s_book_detail.png/revision/latest?cb=20180310083825',
'https://i.pinimg.com/originals/d9/5c/9b/d95c9ba809aa9dd4cb519a225af40f2b.png']
images2 = ['https://static3.srcdn.com/wordpress/wp-content/uploads/2020/07/Quidditch.jpg?q=50&fit=crop&w=960&h=500&dpr=1.5',
'https://specials-images.forbesimg.com/imageserve/5e160edc9318b800069388e8/960x0.jpg?fit=scale']
df['imageUrls'] = images1
df['otherImageUrls'] = images2
# convert your links to html tags
def path_to_image_html(path):
return '<img src="'+ path + '" width="60" >'
pd.set_option('display.max_colwidth', None)
image_cols = ['imageUrls', 'otherImageUrls'] #<- define which columns will be used to convert to html
# Create the dictionariy to be passed as formatters
format_dict = {}
for image_col in image_cols:
format_dict[image_col] = path_to_image_html
display(HTML(df.to_html(escape=False ,formatters=format_dict)))
There has to be a rather easy way to accomplish this I would think. I also tried using PIL to open the image first but to no avail.