How to register an app to respond to a custom URL scheme opening request?

Question

Like this:

NSString *stringURL = @"appname://";
NSURL *url = [NSURL URLWithString:stringURL];
[[UIApplication sharedApplication] openURL:url];

I slightly remember it was necessary to write a value-key to Info.plist. How?

You could see a detailed illustration with the updated 2015 version for Xcode 6 here http://stackoverflow.com/a/18480723/1780492 — BootMaker, May 24 '15 at 08:16

score 7 · Accepted Answer · answered Nov 20 '11 at 12:32

7

Add this to plist screenshot .

The app will by called by @"readtext://" url

answered Nov 20 '11 at 12:32

d.lebedev

Xcode 4 looks completely different! Must I really repeat the bundle identifier for the URL type? It also asks for an Icon and Role. – openfrog Nov 20 '11 at 13:03

score 1 · Answer 2 · edited May 23 '17 at 12:25

1

This seems to be the question that I answered (with screenshots & source code) here.

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And I've posted a full walkthrough of how to do this on my blog.

edited May 23 '17 at 12:25

Community

answered Apr 28 '14 at 07:10

Mike Gledhill

1

You're welcome. It's simple, isn't it, once you can see an example ? It turns a two-hour headache into a 5-minute job !! – Mike Gledhill Aug 07 '14 at 11:47

2 Answers2