I have a table that has a primary key consisting of two columns (product_id, attribute_id). I have another table that needs to reference this table. How can I make a foreign key in the other table to link it to a row in the table with two primary keys?
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3 Answers
94
Something like this ought to do it:
CREATE TABLE MyReferencingTable AS (
[COLUMN DEFINITIONS]
refcol1 INT NOT NULL,
rofcol2 INT NOT NULL,
CONSTRAINT fk_mrt_ot FOREIGN KEY (refcol1, refcol2)
REFERENCES OtherTable(col1, col2)
) ENGINE=InnoDB;
- MySQL requires foreign keys to be indexed, hence the index on the referencing columns
- Use of the constraint syntax enables you to name a constraint, making it easier to alter and drop at a later time if needed.
- InnoDB enforces foreign keys, MyISAM does not. (The syntax is parsed but ignored)

PatrikAkerstrand
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1FWIW, MyISAM does parse and ignore foreign key syntax. And you don't need to declare the index redundantly since MySQL 4.1.2. – Bill Karwin Jun 04 '09 at 22:11
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Also make sure that both tables are InnoDB since, as Bill points out, MyISAM does not support foreign keys. – Abinadi Jun 05 '09 at 03:28
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8I was voted down twice due to the explicit index? Harsh. I did point out that InnoDB was neccessary. – PatrikAkerstrand Jun 05 '09 at 05:50
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You say - `MySQL requires foreign keys to be indexed, hence the index on the referencing columns` - shouldn't that be `REFERENCED COLUMNS`? – Vérace Apr 09 '20 at 02:26
3
There can only be one primary key on a table. The fact in can consist of more than one field does not increase number of primary keys, there's still one.
Since a part of the PK pair is not unique, you obviously have to create a foreign key that refers to two fields as well: REFERENCES t1 (f1, f2).

GSerg
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2
If we want logic for foreign key some like this
FOREIGN KEY COmments(issue_id)
REFERENCES Bugs(issue_id) OR FeatureRequests(issue_id)
Example:
CREATE TABLE Issues (
issue_id int PRIMARY KEY,
status VARCHAR(20)
);
CREATE TABLE Comments (
comment_id int PRIMARY KEY,
issue_type VARCHAR(20), -- "Bugs" or "FeatureRequests"
issue_id BIGINT UNSIGNED NOT NULL,
comment TEXT
);
CREATE TABLE Bugs (
issue_id int PRIMARY KEY,
severity VARCHAR(20),
FOREIGN KEY (issue_id) REFERENCES Issues(issue_id)
);
CREATE TABLE FeatureRequests (
issue_id int PRIMARY KEY,
sponsor VARCHAR(50),
FOREIGN KEY (issue_id) REFERENCES Issues(issue_id)
);
INSERT INTO Issues VALUES(1,'ON'),(2,'ON'),(3,'OFF'),(6,'OFF'),(8,'ON');
INSERT INTO Comments VALUES(1,'Bugs',1,'A'),(2,'Bugs',3,'B'),(3,'Bugs',1,'C'),(4,'Bugs',3,'D'),(5 ,'FeatureRequests',8,'L'),
(6,'FeatureRequests',6,'W'),(7,'FeatureRequests',1,'ZX');
INSERT INTO Bugs VALUES(1,'severity_1'),(3,'severity_for_3');
INSERT INTO FeatureRequests VALUES(2,'sponsor_2_'),(8,'sponsor_for_8'),(1,'sponsor_for_1')
SELECTS :
MariaDB [test]> SELECT * FROM Comments JOIN FeatureRequests ON Comments.issue_i
d = FeatureRequests.issue_id AND Comments.issue_type= 'FeatureRequests';
MariaDB [test]> SELECT * FROM Comments JOIN Bugs ON Comments.issue_id = Bugs.is
sue_id AND Comments.issue_type= 'Bugs';
+------------+------------+----------+---------+----------+----------------+
| comment_id | issue_type | issue_id | comment | issue_id | severity |
+------------+------------+----------+---------+----------+----------------+
| 1 | Bugs | 1 | A | 1 | severity_1 |
| 2 | Bugs | 3 | B | 3 | severity_for_3 |
| 3 | Bugs | 1 | C | 1 | severity_1 |
| 4 | Bugs | 3 | D | 3 | severity_for_3 |
+------------+------------+----------+---------+----------+----------------+
4 rows in set (0.00 sec)

zloctb
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