How to parse or split URL Address in Java?

Question

If I have url address.

https://graph.facebook.com/me/home?limit=25&since=1374196005

Can I get(or split) parameters (avoiding hard coding)?

Like this

https /// graph.facebook.com /// me/home /// {limit=25, sincse=1374196005}

do you want to parse parameters (limit,since) and their value in a map? — kvh, Jul 19 '13 at 01:34
You can use `.split()` to split them based on various delimiters like `/` or `?` . Is that what you want? — Shobhit Puri, Jul 19 '13 at 01:37
@kevinhoo Map is good for me. or getParmKeys(), and getParmVal(parmKey)? — ChangUZ, Jul 19 '13 at 01:37
you may be you are looking for this:http://stackoverflow.com/questions/1667278/parsing-query-strings-in-java — kvh, Jul 19 '13 at 01:46
@ChangUZ before your asking, i use some code i write myself to handle this job. — kvh, Jul 19 '13 at 02:35

score 59 · Accepted Answer · answered Jul 19 '13 at 01:44

59

Use Android's Uri class. http://developer.android.com/reference/android/net/Uri.html

Uri uri = Uri.parse("https://graph.facebook.com/me/home?limit=25&since=1374196005");
String protocol = uri.getScheme();
String server = uri.getAuthority();
String path = uri.getPath();
Set<String> args = uri.getQueryParameterNames();
String limit = uri.getQueryParameter("limit");

answered Jul 19 '13 at 01:44

j__m

9,392
1
32
56

this is what I want. To use getQueryParameterNames in low api level(<11), we can get method in android open source. – ChangUZ Jul 19 '13 at 01:49
(4.2.2 adroid.net.Uri.getQueryParameterNames() method) http://grepcode.com/file/repository.grepcode.com/java/ext/com.google.android/android/4.2.2_r1/android/net/Uri.java#Uri.getQueryParameterNames%28%29 – ChangUZ Jul 19 '13 at 01:50
This is the right answer. Everyone who said anything about `split()`, myself included, read the question too fast. – Doodad Jul 19 '13 at 01:50
1

@ChangUZ fyi, the grepcode link does not appear to be working/live. – AJW Jul 22 '20 at 13:59

score 3 · Answer 2 · answered Jul 19 '13 at 02:11

For pure Java , I think this code should work:

import java.net.URL;
import java.net.URLDecoder;
import java.util.HashMap;
import java.util.Map;

public class UrlTest {
    public static void main(String[] args) {
        try {
            String s = "https://graph.facebook.com/me/home?limit=25&since=1374196005";
            URL url = new URL(s);
            String query = url.getQuery();
            Map<String, String> data = new HashMap<String, String>();
            for (String q : query.split("&")) {
                String[] qa = q.split("=");
                String name = URLDecoder.decode(qa[0]);
                String value = "";
                if (qa.length == 2) {
                    value = URLDecoder.decode(qa[1]);
                }

                data.put(name, value);
            }
            System.out.println(data);
        } catch (Exception e) {
            e.printStackTrace();
        }

    }

}

score 0 · Answer 3 · answered Aug 26 '21 at 18:49

0

In kotlin

https://graph.facebook.com/me/home?limit=25&since=1374196005

import java.net.URI
import android.net.Uri

val uri = URI(viewEvent.qr)
val guid = Uri.parse(uri.fragment).getQueryParameter("c")

answered Aug 26 '21 at 18:49

nmahnic

91
1
2

score 0 · Answer 4 · answered Jun 19 '22 at 15:36

Built-in java.net.URL should serve.

URL url = new URL("https://graph.facebook.com/me/home?limit=25&since=1374196005");

String[] parts = {
   url.getProtocol(), 
   url.getUserInfo(), 
   url.getHost(), 
   url.getPort(), 
   url.getPath(),
   url.getQuery(), 
   url.getRef() 
};

How to parse or split URL Address in Java?

4 Answers4

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