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I have a date string with the format 'Mon Feb 15 2010'. I want to change the format to '15/02/2010'. How can I do this?

FObersteiner
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Nimmy
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  • Duplicate of all of these: http://stackoverflow.com/search?q=%5Bpython%5D+parse+date. Exact duplicate of thise: http://stackoverflow.com/questions/1713594/parsing-dates-and-times-from-strings-using-python – S.Lott Feb 15 '10 at 11:13
  • Does this answer your question? [Converting string into datetime](https://stackoverflow.com/questions/466345/converting-string-into-datetime) – AMC Sep 18 '20 at 20:31

10 Answers10

273

datetime module could help you with that :

datetime.datetime.strptime(input_date_string, input_format).strftime(output_format)

For the specific example you could do :

>>> from datetime import datetime
>>> datetime.strptime('Mon Feb 15 2010', '%a %b %d %Y').strftime('%d/%m/%Y')
'15/02/2010'

Learn more about different formats here.

Samuel RIGAUD
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SilentGhost
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  • `format1` needs to be a string to express the input date string's format. `format2` is the target string format to output. – ThorSummoner Apr 15 '15 at 21:45
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    Tutorial for strptime and its format string: http://www.tutorialspoint.com/python/time_strptime.htm – stenix Oct 29 '15 at 07:56
  • `strptime` and `strftime` are really powerful functions. It's weird I couldn't find them in the python docs – pouya Nov 27 '20 at 12:08
106

You can install the dateutil library. Its parse function can figure out what format a string is in without having to specify the format like you do with datetime.strptime.

from dateutil.parser import parse
dt = parse('Mon Feb 15 2010')
print(dt)
# datetime.datetime(2010, 2, 15, 0, 0)
print(dt.strftime('%d/%m/%Y'))
# 15/02/2010
davidism
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llazzaro
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    dateutil.parse is a better alternative if the exact format of a legal ISO string is unknown. ISO may or may not contain microseconds. It may or may not contain trailing "Z". datetime.strptime is not flexible enough to accomodate for that. – Michael Kariv Dec 12 '13 at 10:51
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    Pase Date should be used with care. parse('12.07.2017') returns datetime(2017, 12, 7, ..) but parse('13.07.2017') returns .datetime(2017, 7, 13, ...) – ego2dot0 Jun 12 '17 at 09:02
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    In `python 3.x` needs to install `python-dateutil` `pip install python-dateutil` – Abhishake Gupta Aug 26 '19 at 15:19
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    Just an update from Michael Kariv, parse provides a param `dayfirst` that will be used to deferentiate between YDM and YMD dates [parse docs](https://dateutil.readthedocs.io/en/stable/parser.html#:~:text=dayfirst%20%E2%80%93%20Whether%20to,defaults%20to%20False).) – Eric Dec 27 '21 at 20:50
37

convert string to datetime object

from datetime import datetime
s = "2016-03-26T09:25:55.000Z"
f = "%Y-%m-%dT%H:%M:%S.%fZ"
out = datetime.strptime(s, f)
print(out)
output:
2016-03-26 09:25:55
anjaneyulubatta505
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28
>>> from_date="Mon Feb 15 2010"
>>> import time                
>>> conv=time.strptime(from_date,"%a %b %d %Y")
>>> time.strftime("%d/%m/%Y",conv)
'15/02/2010'
ghostdog74
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17

As this question comes often, here is the simple explanation.

datetime or time module has two important functions.

  • strftime - creates a string representation of date or time from a datetime or time object.
  • strptime - creates a datetime or time object from a string.

In both cases, we need a formating string. It is the representation that tells how the date or time is formatted in your string.

Now lets assume we have a date object.

>>> from datetime import datetime
>>> d = datetime(2010, 2, 15)
>>> d
datetime.datetime(2010, 2, 15, 0, 0)

If we want to create a string from this date in the format 'Mon Feb 15 2010'

>>> s = d.strftime('%a %b %d %y')
>>> print s
Mon Feb 15 10

Lets assume we want to convert this s again to a datetime object.

>>> new_date = datetime.strptime(s, '%a %b %d %y')
>>> print new_date
2010-02-15 00:00:00

Refer This document all formatting directives regarding datetime.

thavan
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4

@codeling and @user1767754 : The following two lines will work. I saw no one posted the complete solution for the example problem that was asked. Hopefully this is enough explanation.

import datetime

x = datetime.datetime.strptime("Mon Feb 15 2010", "%a %b %d %Y").strftime("%d/%m/%Y")
print(x)

Output:

15/02/2010
SIM
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Gobryas
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3

You may achieve this using pandas as well:

import pandas as pd

pd.to_datetime('Mon Feb 15 2010', format='%a %b %d %Y').strftime('%d/%m/%Y')

Output:

'15/02/2010'

You may apply pandas approach for different datatypes as:

import pandas as pd
import numpy as np

def reformat_date(date_string, old_format, new_format):
    return pd.to_datetime(date_string, format=old_format, errors='ignore').strftime(new_format)

date_string = 'Mon Feb 15 2010'
date_list = ['Mon Feb 15 2010', 'Wed Feb 17 2010']
date_array = np.array(date_list)
date_series = pd.Series(date_list)

old_format = '%a %b %d %Y'
new_format = '%d/%m/%Y'

print(reformat_date(date_string, old_format, new_format))
print(reformat_date(date_list, old_format, new_format).values)
print(reformat_date(date_array, old_format, new_format).values)
print(date_series.apply(lambda x: reformat_date(x, old_format, new_format)).values)

Output:

15/02/2010
['15/02/2010' '17/02/2010']
['15/02/2010' '17/02/2010']
['15/02/2010' '17/02/2010']
nimbous
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2

Just for the sake of completion: when parsing a date using strptime() and the date contains the name of a day, month, etc, be aware that you have to account for the locale.

It's mentioned as a footnote in the docs as well.

As an example:

import locale
print(locale.getlocale())

>> ('nl_BE', 'ISO8859-1')

from datetime import datetime
datetime.strptime('6-Mar-2016', '%d-%b-%Y').strftime('%Y-%m-%d')

>> ValueError: time data '6-Mar-2016' does not match format '%d-%b-%Y'

locale.setlocale(locale.LC_ALL, 'en_US')
datetime.strptime('6-Mar-2016', '%d-%b-%Y').strftime('%Y-%m-%d')

>> '2016-03-06'
DocZerø
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1

use datetime library http://docs.python.org/library/datetime.html look up 9.1.7. especiall strptime() strftime() Behavior¶ examples http://pleac.sourceforge.net/pleac_python/datesandtimes.html

Roman A. Taycher
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  • for the error above nimmyliji you should have done datetime.datetime.strptime("Mon Feb 15 2010", "%a %b %d %Y").strftime("%d/%m/%Y") it gives '15/02/2010' – Roman A. Taycher Feb 15 '10 at 11:20
0

If you dont want to define the input date format then, Install dateparser (pip install dateparser) and,

from dateparser import parse
parse("Mon Feb 15 2010").strftime("%d/%m/%Y")
Vinay Namadi
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